Answer:
Explanation:
false. many elements means a complicated picture, not a simple one.
Complete Question:
Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?
Answer:
a) 51.2 msec. b) 5.12 msec
Explanation:
If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:
The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:
a) BW = 1 Mbps = 10⁶ bps
⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec
b) BW = 10 Mbps = 10⁷ bps
⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec
Answer:
Resource Ownership and Scheduling execution
Explanation:
In process characteristic the characteristic is
- Resource ownership
- Scheduling / Execution
In Resource ownership, the OS performs a protection function where unwanted interference in processes are with resources
In scheduling execution, the process has execution state and scheduled. They can be separated by resource ownership.
The dispatching of the process is the lightweight process, and it is multi-threading. The ability of the operating system supports the single concurrent process.
The process is a unit in the resource protection and protected the CPU and other processes. It contains the multiple thread execution
Each thread contains the running, ready state and saved the thread context and access the memory. Some necessary activities of the various threads are the same address space and the resources.
