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2 years ago

Find the equivalent expression 11(3p+5x)+4x-x

Mathematics

2 answers:

Alex777 [14]2 years ago

5 0

Hello there! :)

Answer:

=33p+58x

*The answer must have a positive sign.*

Step-by-step explanation:

Distributive property: a(b+c)=ab+ac

First, expanded form. Then you can also multiply from left too right.

$11(3p+5x)=33p+55x$

Next, rewrite the problem down.

$33p+55x+4x-x$

And finally, you add by the similar elements. Then you add by the numbers too.

$55x+4x-x=58x$

Final answer: → $33p+58x$

Hope this helps!

Thanks!

Have a great day!

-Charlie

Lyrx [107]2 years ago

3 0

Answer:

The answer is

=33p+58x

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1 year ago

Help me on this please

steposvetlana [31]

I got you hun!

27= 3x is the equation you will need

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2 years ago

Factor the polynomial function over the complex numbers. f(x)=x^4-x^3-2x−4 Enter your answer in the box. f(x) = The answer is: (

Vladimir79 [104]

Answer:

Factors: $(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0$

Step-by-step explanation:

We are given a polynomial:

$f(x)=x^4-x^3-2x-4$

We have to factor the given polynomial into its complex factors.

The factorization can be done as follows:

$f(x)=x^4-x^3-2x-4 = 0\\x^4-x^3-2x-4 = 0\\x^4-4-x^3-2x=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^4-4)-(x^3+2x) = 0\\(x^2+2)(x^2-2)-x(x^2+2) = 0\\(x^2+2)(x^2-2-x) = 0\\(x^2+2)(x^2-x-2) = 0\\(x^2+2)(x^2-2x-+x-2) = 0\\(x^2+2)((x(x-2)+1(x-2))=0\\(x^2+2)(x+1)(x-2)=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^2-(\sqrt{-2})^2)(x+1)(x-2)=0\\(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0$