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3 years ago

6

What is the equation of the line in slope-intercept form that is perpendicular to the line y=3/4x-2 and passes through the point

(–12, 10)?
y =-4/3 x – 6
y = -4/3 x + 6
y = 4/3 x + 26
y = 4/3 x + 10

1 answer:

tatyana61 [14]3 years ago

7 0

Answer:

A

Step-by-step explanation:

You have to plug numbers into point slope formula (make sure to use a slope of -4/3 since its perpendicular) and then solve for y.

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Answer:

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Step-by-step explanation:

Arithmetic sequence concepts:

The general rule of an arithmetic sequence is the following:

$a_{n+1} = a_{n} + d$

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We can expand the general equation to find the nth term from the first, by the following equation:

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The sum of the first n terms of an arithmetic sequence is given by:

$S_{n} = \frac{n(a_{1} + a_{n})}{2}$

In this question:

$a_{1} = -27, d = -21 - (-27) = -15 - (-21) = ... = 6$

We want the sum of the first 37 terms, so we have to find $a_{37}$

$a_{n} = a_{1} + (n-1)*d$

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