What is the equation of the line in slope-intercept form that is perpendicular to the line y=3/4x-2 and passes through the point
(–12, 10)?
y =-4/3 x – 6
y = -4/3 x + 6
y = 4/3 x + 26
y = 4/3 x + 10
1 answer:
Answer:
A
Step-by-step explanation:
You have to plug numbers into point slope formula (make sure to use a slope of -4/3 since its perpendicular) and then solve for y.
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Y=kx
solve for y
-y=4x
divide both sides by -1 aka times -1 both sides
y=-4x
y=kx
the constnat is -4
