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Sergeeva-Olga [200]
3 years ago
15

ZA= 0 Round your answer to the nearest hundredth. 2 6 B​

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
6 0

Answer:

19.47°

Step-by-step explanation:

2 = opposite to A

6 = hypotenus

From trigonometry :

Sin A = opposite / hypotenus

Sin A = 2 / 6

Sin A = 1/3

A = sin^-1(1/3)

A = 19.47°

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Solve x2+12x=-11 by completing the square . Which is the the solution set of the equation?
Dmitriy789 [7]

Answer:

{- 11, - 1 }

Step-by-step explanation:

Since the coefficient of the x² term is 1 , to complete the square

add (half the coefficient of the x-term )² to both sides

x² + 2(6)x + 36 = - 11 + 36 ← complete the square on the left side

(x + 6)² = 25 ( take the square root of both sides

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8 0
3 years ago
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Solve the following equation by completing the square. 3x^2-3x-5=13
mr Goodwill [35]

we'll start off by grouping some

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so we have a missing guy at the end in order to get the a perfect square trinomial from that group, hmmm, what is it anyway?

well, let's recall that a perfect square trinomial is

\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

so we know that the middle term in the trinomial, is really 2 times the other two without the exponent, well, in our case, the middle term is just "x", well is really -x, but we'll add the minus later, we only use the positive coefficient and variable, so we'll use "x" to find the last term.

\bf \stackrel{\textit{middle term}}{2(x)(?)}=\stackrel{\textit{middle term}}{x}\implies ?=\cfrac{x}{2x}\implies ?=\cfrac{1}{2}

so, there's our fellow, however, let's recall that all we're doing is borrowing from our very good friend Mr Zero, 0, so if we add (1/2)², we also have to subtract (1/2)²

\bf \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2-\left[ \cfrac{1}{2} \right]^2 \right)=6\implies \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2 \right)-\left[ \cfrac{1}{2} \right]^2=6 \\\\\\ \left(x-\cfrac{1}{2} \right)^2=6+\cfrac{1}{4}\implies \left(x-\cfrac{1}{2} \right)^2=\cfrac{25}{4}\implies x-\cfrac{1}{2}=\sqrt{\cfrac{25}{4}} \\\\\\ x-\cfrac{1}{2}=\cfrac{\sqrt{25}}{\sqrt{4}}\implies x-\cfrac{1}{2}=\cfrac{5}{2}\implies x=\cfrac{5}{2}+\cfrac{1}{2}\implies x=\cfrac{6}{2}\implies \boxed{x=3}

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