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jeka57 [31]
4 years ago
13

A​ student's course grade is based on one midterm that counts as 5​% of his final​ grade, one class project that counts as 25​%

of his final​ grade, a set of homework assignments that counts as 35​% of his final​ grade, and a final exam that counts as 35​% of his final grade. His midterm score is 72​, his project score is 83​, his homework score is 91​, and his final exam score is 74. What is his overall final​ score? What letter grade did he earn​ (A, B,​ C, D, or​ F)? Assume that a mean of 90 or above is an​ A, a mean of at least 80 but less than 90 is a​ B, and so on.His overall final score is nothing.
Mathematics
1 answer:
Mumz [18]4 years ago
7 0

Answer:

His overal final score is 81.2. His letter grade is a B.

Step-by-step explanation:

Weighed average:

The sum of all values multiplied by it's weight. The weight is a proportion(a value between 0 and 1).

So.

Score of 72 on the midterm, which counts 5%.

Score of 83 on the project score, which counts 25%.

Score of 91 on homework assignments, which counts 35%.

Score of 74 on the final exam, which counts 35%.

His grade is:

G = 72*0.05 + 83*0.25 + 91*0.35 + 74*0.35 = 82.1.

His overal final score is 81.2.

At least 80 but less than 90 is a​ B

So his letter grade is a B.

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aniked [119]

Answer:

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b) Using \pi is more accurate because it represents the exact and full value of pi, rather than an estimation or approximation like 3.14.

Step-by-step explanation:

The formula to find the volume of a cone is \frac{1}{3} \pi r^{2} h. We know the radius is 6, so all we need to find is the height, h. By using the Pythagorean theorem, we can see that the height is 10^{2} - 6^{2} = \sqrt{64}, or 8. Plugging in all the values into the formula gives us:

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Hope this helped! :)

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Does anybody have the answer
Gwar [14]

Answer:

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Step-by-step explanation:

remember x comes before y

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The inequality, |x−35|≤6, describes the the range of typing speeds by Ms. Fletcher's students. Find the range of typing speeds f
Natalija [7]

\text{The given  inequality is   } |x−35|≤6

This can be solved as below

|x-35|\leq6 \\ \\ \text{There two possible cases from here}\\ \text{Case-1}\\ \\ x-35\le \:6\\ \\ x-35+35\le \:6+35\\ \\ x\le \:41\\ \\ \text{Case-2}\\ \\ x-35\ge \:-6\\ \\ x-35+35\ge \:-6+35\\ \\ x\ge \:29\\ \\ \text{Hence the required range of solution is}\\ \\ 29\le \:x\le \:41

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