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AlladinOne [14]
1 year ago
15

Which of the following expressions is equivalent to the logarithmic expression below?A.2 log4 8 + log4 xB.log4 8 - 2 log4 xC.2 l

og4 8 - log4 xD.log4 8 + 2 log4 x

Mathematics
1 answer:
Bingel [31]1 year ago
8 0

We are given the logarithm

log_4(\frac{8}{x^2})

Recall that given positive numbers a and b, a property of logarithms is

log_c(\frac{a}{b})=log_c(a)\text{ -log\_c\lparen b\rparen}^

so if we applyt this property to our situation, we get

log_4(\frac{8}{x^2})=log_4(8)\text{ -log\_4\lparen x}^2)

now, we use another property from logarithms, which is: Given numbers a and b, we have that

log_c(a^b)=b\cdot log_c(a)

so, if we apply this property to the second logarithm we get

log_4(x^2)=2\cdot log_4(x)

so our final answer is

log_4(\frac{8}{x^2})=log_4(8)\text{ -2log\_4\lparen x\rparen}

which corresponds to option B

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Read 2 more answers
Please can someone help me?
Debora [2.8K]
If the perimeters are equal, you can form an equation to find x:
x + x + 12 + x + x + 12 = x + 11 + x + 11 + x + 16
4x + 24 = 3x + 38
- 3x
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I hope this helps!
6 0
3 years ago
Who made an error? <br> The correct scale factor= ?
Ostrovityanka [42]

Answer:

reggie made an error

the correct scale factor is 2/3

Step-by-step explanation:

we want to get from A to A', B to B', and ultimately C to C'

to get there, we must multiply each value in each point by the scale factor.

let's start out with reggie's scale factor. he multiplies each value in C by 3/2 to get to C'. we can try this out with one point, e.g. A

for A: 3/2 * (-12, -6) = (-18, -9). this is not A' = (-8, -4)! thus, 3/2 cannot be the scale factor

now, onto hillary's scale factor of 2/3

for A: 2/3 * (-12, -6) = (-8, -4). this is A'! thus, hillary is correct and reggie made an error

the correct scale factor is thus hillary's: 2/3

4 0
2 years ago
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