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irinina [24]
3 years ago
15

The zeros of a parabola are –4 and 2, and (6, 10) is a point on the graph. Which equation can be solved to determine the value o

f a in the equation of the parabola? 6 = a(10 – 4)(10 + 2) 6 = a(10 + 4)(10 – 2) 10 = a(6 – 4)(6 + 2) 10 = a(6 + 4)(6 – 2)
Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
6 0

Answer:

the answer is D

Step-by-step explanation:

Fittoniya [83]3 years ago
3 0
\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
y=a(x- h)^2+ k\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
\stackrel{\textit{zeros\qquad \qquad \qquad }}{
\begin{cases}
x=-4\implies &x+4=0\\
x=2\implies &x-2=0
\end{cases}}
\\\\\\
\stackrel{\textit{factored vertex form}}{y=a(x+4)(x-2)}\qquad (6,10)\textit{ we also know that }
\begin{cases}
x=6\\
y=10
\end{cases}
\\\\\\
10=a(6+4)(6-2)
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Henry counted 350 lockers haily counted 403 lockers how does the 3 in 350 c ompare to the 3 in 403
kramer

the 3 in 350 represents 3 hundred's ( 3 100's ) while the 3 in 403 represents 3 units ( 3 1's )


4 0
4 years ago
The store paid $2.70 for a book and sold it for $6.20. What is the profit as a percent?
Alenkinab [10]

Answer:

129.6% profit

Step-by-step explanation:

1)Firstly in order to find the overall profit you take away $2.70 from $6.20 = $3.50

2)The next step is to put the profit over the amount paid = 3.50/2.70 = 35/27.

3)In order to find the percentaage you multiply 35/27 by 100 = 129.629 recurring. This rounded to 1 decimal place is 129.6%

Thank you for reading, please let me know if I've missed anything out!

5 0
2 years ago
Help geometry what I m jlf <br> Picture provided
Zolol [24]

Answer:

\angle\,JLF = 114^o  which agrees with option"B" of the possible answers listed

Step-by-step explanation:

Notice that in order to solve this problem  (find angle JLF) , we need to find the value of the angle defined by JLG and subtract it from 180^o, since they are supplementary angles. So we focus on such, and start by drawing the radii that connects the center of the circle (point "O") to points G and H, in order to observe the central angles that are given to us as 90^o and 138^o. (see attached image)

We put our efforts into solving the right angle triangle denoted with green borders.

Notice as well, that the triangle JOH that is formed with the two radii and the segment that joins point J to point G, is an isosceles triangle, and therefore the two angles opposite to these equal radius sides, must be equal. We see that angle JOH can be calculated by : 360^o-90^o-138^o=132^o

Therefore, the two equal acute angles in the triangle JOH should add to:

180^o-132^o=48^o resulting then in each small acute angle of measure 24^o.

Now referring to the green sided right angle triangle we can find find angle JLG, using: 180^o-24^o-90^o=66^o

Finally, the requested measure of angle JLF is obtained via: 180^o-66^o=114^o

4 0
3 years ago
Please help me. I can't figure out how to get an equation
Eddi Din [679]
A printer shop purchases a new printer fro $25,000
the equipment depreciates at a rate of 5% each year
the relationship between the value of the printer, y, and the year number, x can represented by the equation y=25,000*0.95^x
year 1: $23,750
year 2: $22,562.50
year 3: $21,434.38  
8 0
4 years ago
What is the coefficient of the second term of the trinomial?
marin [14]
The coefficient of the second term is 18.

What you do is you FOIL the terms:
(3x+3)(3x+3)\\ Multiply\ the\ first\ terms\ together:\\ 3x*3x=9x^{2}\\ Then\ the\ outer\ terms:\\ 3x*3=9x\\ Next,\ the\ inner\ terms:\\ 3x*3=9x\\ Finally,\ multiply\ the\ last\ terms:\\ 3*3=9\\ Putting\ the\ terms\ together:\\ 9x^{2}+9x+9x+9=9x^{2}+18x+9\\\\ Since\ (3x+3)^{2}=9x^{2}+Bx+9=9x^{2}+18x+9,\ then \ B=18.
7 0
3 years ago
Read 2 more answers
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