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irinina [24]
3 years ago
15

The zeros of a parabola are –4 and 2, and (6, 10) is a point on the graph. Which equation can be solved to determine the value o

f a in the equation of the parabola? 6 = a(10 – 4)(10 + 2) 6 = a(10 + 4)(10 – 2) 10 = a(6 – 4)(6 + 2) 10 = a(6 + 4)(6 – 2)
Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
6 0

Answer:

the answer is D

Step-by-step explanation:

Fittoniya [83]3 years ago
3 0
\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
y=a(x- h)^2+ k\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
\stackrel{\textit{zeros\qquad \qquad \qquad }}{
\begin{cases}
x=-4\implies &x+4=0\\
x=2\implies &x-2=0
\end{cases}}
\\\\\\
\stackrel{\textit{factored vertex form}}{y=a(x+4)(x-2)}\qquad (6,10)\textit{ we also know that }
\begin{cases}
x=6\\
y=10
\end{cases}
\\\\\\
10=a(6+4)(6-2)
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Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
Help math help 50 points I need alll the questions answered. Help ASAP no links or imma report you.
Ganezh [65]

Answer:

Step-by-step explanation:

x+y = 6

y = (6-x)

7x +12y = 52

7x+12(6-x) = 52

7x +72 -12x = 52

-5x = -20

x= 4     4 days at $7  = $28

           2 days at $12 = $24

 28+24 = 52

4 0
3 years ago
What is the multiplacation problem for sandy walk 26 miles in a month. If she were consistent in her walking for 2 years, how ma
Svetllana [295]

Answer:

624 miles

Step-by-step explanation:

We know that there are 12 months in a year, and you need to find out the total miles she walks in two years, which is 24 months.

So we multiply 26(24)

This is equal to 624 miles

6 0
3 years ago
Read 2 more answers
What do I do? what's Ax??
Liono4ka [1.6K]

A=\left[\begin{array}{ccc}5&-4\\3&6\end{array}\right] \\\\A_x=\left[\begin{array}{ccc}12&-4\\66&6\end{array}\right]

|A_x|=\left|\begin{array}{ccc}12&-4\\66&6\end{array}\right|=(12)(6)-(66)(-4)=72+264=336

5 0
3 years ago
PLEASE HELP I WILL GIVE 25 POINTS AND BRAINLIEST ANSWER FOR RIGHT ANSWER
steposvetlana [31]
The answer would be $3 becaus of x = $12 and y = $9. $12 - $9 = $3.
4 0
3 years ago
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