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irinina [24]
3 years ago
15

The zeros of a parabola are –4 and 2, and (6, 10) is a point on the graph. Which equation can be solved to determine the value o

f a in the equation of the parabola? 6 = a(10 – 4)(10 + 2) 6 = a(10 + 4)(10 – 2) 10 = a(6 – 4)(6 + 2) 10 = a(6 + 4)(6 – 2)
Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
6 0

Answer:

the answer is D

Step-by-step explanation:

Fittoniya [83]3 years ago
3 0
\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
y=a(x- h)^2+ k\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
\stackrel{\textit{zeros\qquad \qquad \qquad }}{
\begin{cases}
x=-4\implies &x+4=0\\
x=2\implies &x-2=0
\end{cases}}
\\\\\\
\stackrel{\textit{factored vertex form}}{y=a(x+4)(x-2)}\qquad (6,10)\textit{ we also know that }
\begin{cases}
x=6\\
y=10
\end{cases}
\\\\\\
10=a(6+4)(6-2)
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