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horsena [70]
3 years ago
15

Solve by elimination -5x+8y=-27 -8x+7y=-20

Mathematics
1 answer:
Anika [276]3 years ago
7 0

Answer:

x = -1 , y = -4

Step-by-step explanation by elimination:

Solve the following system:

{8 y - 5 x = -27 | (equation 1)

7 y - 8 x = -20 | (equation 2)

Swap equation 1 with equation 2:

{-(8 x) + 7 y = -20 | (equation 1)

-(5 x) + 8 y = -27 | (equation 2)

Subtract 5/8 × (equation 1) from equation 2:

{-(8 x) + 7 y = -20 | (equation 1)

0 x+(29 y)/8 = (-29)/2 | (equation 2)

Multiply equation 2 by 8/29:

{-(8 x) + 7 y = -20 | (equation 1)

0 x+y = -4 | (equation 2)

Subtract 7 × (equation 2) from equation 1:

{-(8 x)+0 y = 8 | (equation 1)

0 x+y = -4 | (equation 2)

Divide equation 1 by -8:

{x+0 y = -1 | (equation 1)

0 x+y = -4 | (equation 2)

Collect results:

Answer:  {x = -1 , y = -4

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A buoy oscillates in simple harmonic motion y= A cos cos as waves move past it. The buoy moves a total of 3.5 feet (vertically)
NNADVOKAT [17]

Answer:

a) y = 1.75 ft cos (\frac{\pi}{5}t)

b) v(t) = -1.0995 sin (\frac{\pi}{5}t)

Step-by-step explanation:

Part a

Since the buoy oscillates in simple harmonic motion the equation to model this is given by:

y = A cos (wt +\theta)

For this case from the info given we know that:

2A = 3.5 , A = \frac{3.5}{2}= 1.75 ft

"It returns to its high point every 10 seconds." That means period =10 T =10s, and the angular frequency can be founded like this:

w = \frac{2\pi}{10}= \frac{\pi}{5}

Assuming that the value for the phase is \theta =0 our model equation is given by:

y = 1.75 ft cos (\frac{\pi}{5}t)

Part b

From definition we can obtain the velocity with the derivate of the position function and if w calculate the derivate we got this:

\frac{dy}{dt}= v(t) = -1.75 ft (\frac{\pi}{5}) sin (\frac{\pi}{5}t)

v(t) = -1.0995 sin (\frac{\pi}{5}t)

6 0
3 years ago
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