Question

a garden is in the shape of a rectangle and has a perimeter of 70 yards. the length of the garden is 5 more than twice the width. find the dimensions of the garden.

Answer 1

If the length of the garden is 5 more than twice the width, then length = 2 X width + 5.
P = 70
L= 2W + 5
P = 2 X (L + W)
70 = 2 X ((2W+5) + W))
You can take the + 5 out at this point by multiplying it by the 2 outside the brackets (5 for each length)
70 - (2X5) = 2X ((2W) + W)
70 - 10 = 2 X (2W + W)
60 = 2 (3W)
60 = 2*3W
60 = 6W
10 = W
The width is 10.
So what's the length? 2W + 5
Length = 2 * 10 + 5
Length = 25.

Length is 25, width is 10.

Check: 70 = 2 (25 + 10)
70 = 2(35)
70 = 70
Correct!