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2 years ago

Factorise : x^2-9x-70 Step by Step

Mathematics

2 answers:

tensa zangetsu [6.8K]2 years ago

8 0

Answer:

Step-by-step explanation:

x^2 - 9x - 70

we need to find two numbers whose sum is -9 and product id -17

The numbers are -14 and 5

By splitting the middle term,

x^2 - 14x + 5x - 70

= x ( x - 14 ) + 5 ( x - 14 )

( x + 5 ) ( x - 14 )

Hope this helps

Plz mark as brainliest!!!!!

denis23 [38]2 years ago

3 0

Answer:

Step-by-step explanation:

Sum = -9

Product = -70

Factors = -14 , 5

x² - 9x - 70 = x² + 5x - 14x + (-14) * 5

=x(x + 5) - 14(x + 5)

= (x + 5)(x - 14)

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20/45 in simplest form

san4es73 [151]

20/45 would be 4/9 in simplest form. hope that helped

7 0

3 years ago

Read 2 more answers

For the following system, use the second equation to make a substitution for why in the first equation. Will mark brainlyest!

Alona [7]

Answer:

Step-by-step explanation:

get y by itself in the second equation: y= 2x-3

substitute this into the y of the first equation:

2x+2x-3= 5

7 0

3 years ago

A) Let X be a random variable that can assume only positive integer values, and assume its probability function is P(X -n) A/3^n

kramer

Answer:

a) The value of A = 2

b) The value of $B = \dfrac{1}{12}$

Step-by-step explanation:

Given that:

X should be the random variable that assumes only positive integer values.

The probability function; $P[X = n] = \dfrac{A}{3^n}$ for some constant A and n ≥ 1.

Then, let $\sum \limits ^{\infty}_{n =1} P[X =n] = 1$

This implies that:

$A \sum \limits ^{\infty}_{n =1} \dfrac{1}{3^n}= 1$

$A \times \dfrac{\dfrac{1}{3}}{1 - \dfrac{1}{3}} = 1$

$A \times \dfrac{\dfrac{1}{3}}{\dfrac{2}{3}} = 1$

$A \times \dfrac{1}{2}=1$

A = 2

Thus, the value of A = 2

Suppose X represents a e constant A (n> 1). Find A.

b) Let X be a continuous random variable that can assume values between 0 and 3

Then, the density function of x is:

$f_x(x) = \left \{ {{B(x^2+1)} \ \ \ 0 \le x \le 3 \ \ \ \atop {0} \ \ \ otherwise} \right.$

where; B is constant.

Then, using the property of the probability density function:

$\int ^3_0 \ B (x^2+1 ) \ dx = 1\\$

Taking the integral, we have:

$B \Big [\dfrac{x^3}{3} +x \Big ]^3_0 = 1$

$B \Big [\dfrac{3^3}{3} +3 \Big ]= 1$

$B \Big [\dfrac{27}{3} +3 \Big ] = 1$

B [ 9 +3 ] = 1

B [ 12 ] = 1

Divide both sides by 12

$B = \dfrac{1}{12}$

5 0

3 years ago

1. tanD = 2. sinF = 3. tanF = 4. cosF =

Fofino [41]

Tangent is opposite side over adjacent side.
Sine is opposite side over hypotenuse.
Cosine is adjacent side over hypotenuse.
1. Tan D = d/f
2. Sin F = f/e
3. Tan F = f/d
4. Cos F = d/e

4 0

3 years ago

If a1=10 and an+1=-5an-1 then find the value of a4 Please explain!

Umnica [9.8K]

Answer:

$a_4=-1271$

Step-by-step explanation:

We are given that:

$a_1=10$

And:

$a_{n+1}=-5a_n-1$

And we want to find:

$a_4$

This is a recursive formula. So we can simply substitute in each value. For instance, a₂ will be:

$a_2=a_{(1)+1}=-5a_{1}-1=-5(10)-1=-51$

Thus, a₃ will be:

$a_3=a_{(2)+1}=-5a_2-1=-5(-51)-1=254$

Finally, a₄ will be:

$a_4=a_{(3)+1}=-5a_3-1=-5(254)-1=-1271$

4 0

2 years ago

Factorise : x^2-9x-70 Step by Step​

Factorise : x^2-9x-70 Step by Step