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jeka57 [31]
3 years ago
6

The plot shows the temperatures (in ºF) for a group of children who visited a doctor’s office. A plot shows the temperature of c

hildren at a doctor's office. 1 child had a temperature of 96 degrees; 2, 97 degrees; 5, 98 degrees; 2, 99 degrees; 1, 100 degrees. What conclusions can be drawn from the data set? Check all that apply.
Mathematics
1 answer:
marshall27 [118]3 years ago
8 0

Answer:

See below.

Step-by-step explanation:

1) the measure of center are the same  

3) there is little variability in the data

4) the average temperature is 98

5) the data is clustered around the mean

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Answer:

2/3

Step-by-step explanation:

1/2 ÷3/4 =

1/2 ×4/3 =  4/6

4/6 ÷2  = 2/3 is the answer

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Show that if the vector field F = Pi + Qj + Rk is conservative and P, Q, R have continuous first-order partial derivatives, then
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Answer:

It is proved that \frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}

Step-by-step explanation:

Given vector field,

F=P\uvec{i}+Q\uvec{j}+R\uvec{k}

Where,

P=f_x=\frac{\partial f}{\partial x}, Q=f_y=\frac{\partial f}{\partial y}, R=f_z=\frac{\partial f}{\partial z}

To show,

\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}

Consider,

\frac{\partial P}{\partial y}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial y\partial x}=\frac{\partial^2 f}{\partial x\partial y}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial y})=\frac{\partial Q}{\partial x}

\frac{\partial P}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial z\partial x}=\frac{\partial^2 f}{\partial x\partial z}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial x}

\frac{\partial Q}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial y})=\frac{\partial^2 f}{\partial z\partial y}=\frac{\partial^2 f}{\partial y\partial z}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial y}

Hence proved.

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A referee was standing on a certain yard line as the first quarter ended. He walked 41 3/ 4 yards to a yard line with the same n
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