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3 years ago

15

Plot the points (2, 4) and (2, -8) on the coordinate plane below.

1 answer:

Charra [1.4K]3 years ago

8 0

Answer:

12

Step-by-step explanation:

4 - (-8) =12

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4x-5=19 please help thank you

frosja888 [35]

Answer:

x=6

Step-by-step explanation:

$4x - 5 = 19$

$4x = 19 + 5$

$4x = 24$

$x = \frac{24}{4}$

$x = 6$

4 0

2 years ago

Read 2 more answers

In the diagram below, x is a whole number. what is the smallest possible value for x?

lesya692 [45]

Answer:

The smallest possible value for x is $9\ units$

Step-by-step explanation:

we know that

The <u>Triangle Inequality Theorem</u>. states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side

so

$x+x>17\\2x>17\\x>8.5\ units$

The value of x must be greater than $8.5\ units$

so

If x must be a whole number

therefore

The smallest possible value for x is $9\ units$

3 0

3 years ago

A. 2b + 8 - 5b + 3 = -13 + 8b – 5

MrRa [10]

Solution
-3b + 11 = -18 + 8b
-3b - 8b = -18 - 11
-11b = -29
b = 29/11

8 0

3 years ago

Read 2 more answers

explain how it is possible that all proportional relationships are linear functions but not all linear functions are proportiona

OLEGan [10]

Proportional and linear functions are almost identical in form. The only difference is the addition of the “b” constant to the linear function. Indeed, a proportional relationship is just a linear relationship where b = 0, or to put it another way, where the line passes through the origin (0,0).

You’re welcome

6 0

3 years ago

Write a quadratic function, in standard form, that fits the set of points. Solve it as a system of three equations. (-4, 9), (0,

Tresset [83]

Answer:

$\boxed{y=2x^2+4x-7}$

Step-by-step explanation:

Let the quadratic function be

$y=ax^2+bx+c$

We substitute $(-4,9)$ into the equation to obtain;

$9=a(-4)^2+b(-4)+c$

$\Rightarrow 9=16a-4b+c---(1)$

We substitute $(0,-7)$ to obtain;

$-7=a(0)^2+b(0)^2+c$

$\Rightarrow c=-7---(2)$

We finally substitute $(1,-1)$ to obtain;

$-1=a(1)^2+b(1)^2+c$

$\Rightarrow -1=a+b+c---(3)$

We put equation (2) into equation (1) to get;

$9=16a-4b-7$

$16a-4b=16$

$\Rightarrow 4a-b=4---(4)$

$\Rightarrow -1=a+b-7$

$\Rightarrow a+b=6---(5)$

We add equation (4) and (5) to get;

$4a+a=6+4$

$\Rightarrow 5a=10$

$\Rightarrow a=2$

We put $a=2$ into equation (5) to get;

$2+b=6$

$\Rightarrow b=6-2$

$\Rightarrow b=4$

The reqiured quadratic function is

$y=2x^2+4x-7$

7 0

3 years ago