Answer:
t = 5.46 secs and t = 2.42 secs
Step-by-step explanation:
The distance of the ball from the ground is given by:
When the ball is at a distance 211 ft from the ground, that means s(t) = 211 ft. we need to find t:
Using the quadratic formula:
and 
where a = 16, b = 126 and c = 211
Hence:
and 
and 
and 
and 
and 
=> t = 5.46 secs and t = 2.42 secs
This means that the ball will be at 211 feet at two different times, first, after 2.42 seconds and then after 5.46 seconds.
This makes sense because the ball is projected upwards, which means that when going up, it attains 211 feet and also, when coming back down, it also attains 211 feet.
Answer:
I'm guessing you want to know the distance I think so the distance is √20
Step-by-step explanation:
Distance formula
√(x2-x1)^2+(y2-y1)^2
√(2-(-2)^2+(-5-(-3)^2
√16+4= 20
√20
finding the square root gives you a long decimal which is 4.472135954999 and so on
Answer:
See below...
Step-by-step explanation:
For a function whose formula is in this pattern:
Amplitude: 
Period: 
Phase Shift: C
In this question, 
Amplitude: 4
Period: 
Phase Shift: 
There is no vertical shift, so the midline is the x-axis whose equation is y = 0.
Also, because there is no vertical shift, the maximum is 4 and the minimum is -4.
The graph is attached.
Answer:
X = 0
Step-by-step explanation:
