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Tanzania [10]
3 years ago
13

Are there 5 100s in 0.305?

Mathematics
2 answers:
34kurt3 years ago
4 0

no, 5 is in the thousandths place

sertanlavr [38]3 years ago
4 0

Answer:

Step-by-step explanation:

No there is only .3 hundreds

You might be interested in
QUESTION TWO Determine whether or not a constant function can be
Sveta_85 [38]
<h3>Answers:</h3>
  • (a) It is <u>never</u> one-to-one
  • (b) It is <u>never</u> onto

=========================================================

Explanation:

The graph of any constant function is a horizontal flat line. The output is the same regardless of whatever input you select. Recall that a one-to-one function must pass the horizontal line test. Horizontal lines themselves fail this test. So this is sufficient to show we don't have a one-to-one function here.

Put another way: Let f(x) be a constant function. Let's say its output is 5. So f(x) = 5 no matter what you pick for x. We can then show that f(a) = f(b) = 5 where a,b are different values. This criteria is enough to show that f(x) is not one-to-one. A one-to-one function must have f(a) = f(b) lead directly to a = b. We cannot have a,b as different values.

----------------------------

The term "onto" in math, specifically when it concerns functions, refers to the idea of the entire range being accessible. If the range is the set of all real numbers, then we consider the function be onto. There's a bit more nuance, but this is the general idea.

With constant functions, we can only reach one output value (in that example above, it was the output 5). We fall very short of the goal of reaching all real numbers in the range. Therefore, this constant function and any constant function can never be onto.

4 0
3 years ago
Due yesterday <br><br> Even if ur sure its correct j send it, ill turn in anything
Alisiya [41]

Answer:

A)8000

B) 1296a^4

C) 9x^2

D)100000000

E)0.00097656

F)x^⁶

G)y^11

Step-by-step explanation:

3 0
2 years ago
Simplfy 2(v-4)-5v helpp meee
laila [671]

Step-by-step explanation:

2(v-4)-5v

= 2v-8-5v

= -3v-8

8 0
3 years ago
Find the general solution to y′′+7y′=0y′′+7y′=0. give your answer as y=..
ExtremeBDS [4]
Try this option:
1. characteristic equation is:
a²+7a=0;
\left[\begin{array}{ccc}a=0\\ a=-7\end{array}\right
2. y=C₁+C₂e⁻⁷ˣ.
4 0
3 years ago
What do you need to know about two figured to be convinced that the two figures are congruent?
MrRissso [65]
It depends on what the figure looks like. You could have SSS is If three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent. As you can see, the SSS Postulate does not concern itself with angles at all.
SAS is have two triangles where we know two angles and the included side are equal.
ASA If two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent
Idk what the figures you are talking about but I gave u some for triangles. If you comment back I can help u if you give me the figures you are talking about
5 0
3 years ago
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