9514 1404 393
Answer:
Step-by-step explanation:
The tangent of the angle can be found using the identity for the tangent of the difference of angles.
tan(α-β) = (tan(α) -tan(β))/(1 +tan(α)tan(β))
The tangent of the angle of each vector is the ratio of the j coefficient to the i coefficient.
tan(α) = -2/3
tan(β) = 4/7
tan(α-β) = (-2/3 -4/7)/(1 +(-2/3)(4/7))
= (-14-12)/(21 -8) = -26/13 = -2
Then the magnitude of the angle between the vectors is ...
arctan(2) ≈ 63.43°
↝ x-intercept
↝ y-intercept
y = -5
↝ means that the shade/area is below the graph as shown in the first picture.
↝ x-intercept
↝ y-intercept
y = -3
↝ Since it's "≤" therefore. The shade/area is below the graph. For second picture.
First picture is first inequality
Second picture is second inequality.
Actually Welcome to the Concept of the areas.
Since we know that, radius = diameter /2
here, => d = 2r ,
hence we use the formula as,
A = πr^2 ,
here option d.) is correct.
Answer:
39x
Step-by-step explanation:
28x + 11= 39x
I hope this helps
Have a great day!
