Answer:
Therefore there total of 39 children presented in group of people who attended a ball game.
Step-by-step explanation:
Given:
Total people present=52 .
And there are 3 times children as adults
To Find:
No.of Children Present in Group.
Solution:
<em>Consider 'x' be the children and 'y' be Adults presented in group.</em>
<em />
So there are total of 52 people.
Therefore Equation becomes,
x+y=52.
And also there are 3 times children presented in group as adults were.
So
Children=3 times adults
i.e.x=3y
Using in above Equation we get ,
x+y=52
3y+y=52
4y=52
y=52/4
y=13
Hence there are 13 adults presented in group
So ,
No.of Children=x=3y
=3(13)
=39
No.of.Children =39
Answer:
Please see the attachments. For reasons I cannot fathom, the Brainly censor seems to think there are unapproved words contained in this text, so I cannot post it as text. Among other things, that means you probably will not be able to copy and paste the formulas into your spreadsheet—you will have to type them.
I apologize if you are offended by any of the words contained in this answer. I hope you will take them in the intended context—a math problem about the use of Excel.
(tanθ + cotθ)² = sec²θ + csc²θ
<u>Expand left side</u>: tan²θ + 2tanθcotθ + cot²θ
<u>Evaluate middle term</u>: 2tanθcotθ =
= 2
⇒ tan²θ + 2+ cot²θ
= tan²θ + 1 + 1 + cot²θ
<u>Apply trig identity:</u> tan²θ + 1 = sec²θ
⇒ sec²θ + 1 + cot²θ
<u>Apply trig identity:</u> 1 + cot²θ = csc²θ
⇒ sec²θ + csc²θ
Left side equals Right side so equation is verified
131/5 divided by 11/1
to divide by fractions, you multiply by the reciprocal and the reciprocal of 11/1 is 1/11...
131/5•1/11 and you just multiply across so the answer is every 131/55 miles. if you want it as a mixed number, it's 2 21/55