WORK:
8×2 = 16
3×2 = 6
ANSWER:
D.) 16/6
Before:
The number of goats =60%
The number of cows = 100%
Using ratio
Cows : Goats
60 : 100 reduced to simplest term
C:G
3:5
After
The number of cows = 100%
The number of goats = 60%
Using ratio
C:G
100:60 reduced to simplest term
C:G
5:3
Number of cows remained constant. Therefore find the common multiple.
Before
C:G
15:25
After
C:G
15:9
Find the difference in the units of goats
(a)25 - 19= 16
16 units =80
1 unit = 5
15 units (cows) = 5 x 15 = 75
There were 75 cows.
(B)
Number of goats at first
25 units = 5 x 25 = 125
Therefore percentage= 80/125 x 100
= 64%
M(slope) = Δy/Δx = 8-(-6)/-4-(-3) = 14/-1 = -14
Its 15 since 36 goes into 540 that many times
