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Factorise using suitable identities (0.1x-0.2y)^2
1 answer:
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If one of our zeros is 4, then the factor is x-4. If the second zero is 5i, then the conjugate root theorem says there HAS to be a root that is -5i. So our 3 factors are (x-4)(x+5i)(x-5i). We will FOIL out these factors to get the polynomial. Let's start with the ones that contain the imaginary numbers. Doing that mutliplication we get x^2-25i^2. i^2 is equal to -1, so what that expression simplifies down to is 
. Now we will multiply in that last factor of (x-4): 
. FOILing out we have 
. There you go!
Answer:
<h2>In the attachment.</h2>Step-by-step explanation:
Convert the given equation to the form y = mx + b:
<em>add x to both sides</em>
<em>divide both sides by 2</em>
It's a linear function.
We need only two points to plot the graph. Select any two x values, insert into the equation and calculate y values.
for x = 1
for x = -5
