Factorise using suitable identities (0.1x-0.2y)^2
1 answer:
Answer:
Step-by-step explanation:
(a - b)² = a² - 2ab + b²
a = 0.1x
b = 0.2y
(0.1x - 0.2y)²= (0.1x)² - 2*0.1x*0.2y + (0.2y)²
= (0.1)²x² - 0.04xy + (0.2)²y²
= 0.01x² - 0.04xy + 0.04y²
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Answer:

Step-by-step explanation:


Your Answer is 2/7. I hope this helped
Step-by-step explanation:
Given
f(x) = -5x - 1
and
g(x) = 2x + 2
Now
f(3) = - 5 * 3 - 1
= -15 -1
= -16
Also
g(-4) = 2 * (-4) + 2
= - 8 + 2
= - 6
1. 5-x=15
2. x+12<25
3. 2x-5>47
4. 4(8+x)=88
5.

6. x+15=-8
7. x-48=62
8. 10÷2x<1/4
9.

10. 2+2x=48
11. 4x+8=20
12. 6x+19=79
13. 6x-8>15
14. x+(x+1)=29
15. x+(x+2)=46