2 years ago

Factorise using suitable identities (0.1x-0.2y)^2

Mathematics

1 answer:

Sav [38]2 years ago

3 0

Answer:

Step-by-step explanation:

(a - b)² = a² - 2ab + b²

a = 0.1x

b = 0.2y

(0.1x - 0.2y)²= (0.1x)² - 2*0.1x*0.2y + (0.2y)²

= (0.1)²x² - 0.04xy + (0.2)²y²

= 0.01x² - 0.04xy + 0.04y²

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