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Delicious77 [7]
3 years ago
8

Which of these are rational? (Select all that apply)

Mathematics
1 answer:
Anon25 [30]3 years ago
6 0
ABCEG. Not D because non terminating numbers are irrational, same goes for Pi
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Who can answer this question
lyudmila [28]
The answer is: c
Explination 30-9=21
8 0
3 years ago
Identify the percent of change as an increase or a decrease.<br><br> 75 people to 25 people
Anna11 [10]

Answer:

1/3

Step-by-step explanation:

im not sure what answer you were looking for but hope this helps

6 0
2 years ago
F left parenthesis x right parenthesis equals 9 x cubed plus 2 x squared minus 5 x plus 4 and g left parenthesis x right parenth
Jet001 [13]
The answer is 2x(2x²+x+1).

When we subtract polynomials we combine like terms:
(9x³+2x²-5x+4)-(5x³-7x+4)

9x³-5x³=4x³
2x²- 0 = 2x²
-5x--7x=-5x+7x=2x
4-4=0

This gives us 
4x³+2x²+2x

Each of these is divisible by 2, and each has an x, so we factor those out:
2x(                        )

4x³/2x = 2x²:
2x(2x²                   )

2x²/2x=x:
2x(2x²+x               )

2x/2x = 1:
2x(2x²+x+1)
3 0
3 years ago
Write the expression in repeated multiplication form. Then write the expression as a power. (-8)^3*(-8)^4 The expression in repe
Makovka662 [10]

Given:

The expression is

(-8)^3\cdot (-8)^4

To find:

The expression in repeated multiplication form and then write the expression as a power.

Solution:

We have,

(-8)^3\cdot (-8)^4

The repeated multiplication form of this expression is

=[(-8)\cdot (-8)\cdot (-8)]\cdot [(-8)\cdot (-8)\cdot (-8)\cdot (-8)]

=(-8)\cdot (-8)\cdot (-8)\cdot (-8)\cdot (-8)\cdot (-8)\cdot (-8)

Clearly, (-8) is multiplied seven times by itself. So,

=(-8)^7

Therefore, the repeated multiplication form of the given expression is (-8)\cdot (-8)\cdot (-8)\cdot (-8)\cdot (-8)\cdot (-8)\cdot (-8) and the expression as single power is (-8)^7.

7 0
3 years ago
It took Mrs. Johnson 1/2 an hour to walk 2 1/2 miles. What is her speed in miles per hour?​
Arisa [49]

Answer:

I think its 5 mph

Step-by-step explanation:

3 0
4 years ago
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