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TEA [102]
2 years ago
14

A health food store makes trail mix using dried fruit and nuts. The cost of the dried fruit is $2.50 per

Mathematics
2 answers:
3241004551 [841]2 years ago
6 0

Answer:

Option A.

Step-by-step explanation:

The total cost of the mix is the sum of the cost for dried fruit and nuts.

Recognizing the first term has a coefficient of 2.5, which is the cost of the dried fruit per pound, the term 2.5x represent the total cost of the dried fruit, and x be the number of pound of dried fruit.

Vinil7 [7]2 years ago
5 0

Answer:

cost of dried fruit per pound=2.5 $/pound

cost of nuts per pound =2 $/pound

total cost=225$ =cost of dried fruit +total cost of nuts

To find the cost of dried fruit we need to multiply cost of dried fruit per pound and the number of bounds hence 2.5 x where x is the number of bounds

which is the total cost of dried fruit and consequently 2y is total cost of nuts where y is the weight of nuts in pound

Step-by-step explanation:

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Five carpenters worked 15 &amp; 3/4, 15 &amp; 1/4, 17 &amp; 1/2, 12 &amp; 1/2 and 17 &amp; 1/2 hours respectively. What was the
azamat

<u>The total </u><u>labor cost</u><u>  of the carpenters is $2296.91</u>

The carpenters worked 15\frac{3}{4} , 15\frac{1}{4}, 17\frac{1}{2}, 12\frac{1}{2}, 17\frac{1}{2}

<h3>Conversion of Fraction</h3>

Let's convert the mixed fraction to improper fraction

So, we would have

  • 63/4,
  • 61/4,
  • 35/2,
  • 25/2
  • 35/2.
<h3>Working Cost</h3>

Let's sum it up and multiply by the working cost per hour

63/4 + 61/4 + 35/2 + 25/2 + 35/2 =78.5

  • The total labor cost is = total hours worked * hourly rate.

This becomes 78.5*29.26=2296.91

<u>The total labor cost is $2296.91</u>

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3 0
3 years ago
A business school has a goal that the average number of years of work experience of its MBA applicants is more than three years.
gizmo_the_mogwai [7]

Answer:

z=\frac{3.1-3}{\frac{2.449}{\sqrt{47}}}=0.280    

p_v =P(z>0.280)=0.390  

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its NOT significant higher than 0.3 at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=3.1 represent the sample mean

\sigma=\sqrt{6} represent the sample standard deviation for the sample

n=47 sample size  

\mu_o =3 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 3, the system of hypothesis would be:  

Null hypothesis:\mu \leq 3  

Alternative hypothesis:\mu > 3  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{3.1-3}{\frac{2.449}{\sqrt{47}}}=0.280    

P-value

Since is a one side test the p value would be:  

p_v =P(z>0.280)=0.390  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its NOT significant higher than 0.3 at 1% of signficance.  

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lbvjy [14]

Answer:

Perimeter of a triangle = add all sides

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x = 8

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Because if you did not you would not have a exact answer.

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