Answer:
∠A = ∠C = 60°
∠B = ∠D = 120°
Step-by-step explanation:
In quad. DPBQ, by angle sum property we have
∠PDQ + ∠DPB + ∠B + ∠BQD = 360°
60° + 90° + ∠B + 90° = 360°
∠B = 360° – 240°
Therefore, ∠B = 120°
But ∠B = ∠D = 120° opposite angles of parallelogram
As, AB || CD opposite sides of a parallelogram
∠B + ∠C = 180° sum of adjacent interior angles is 180°
120° + ∠C = 180°
∠C = 180° – 120° = 60°
Hence ∠A = ∠C = 60° Opposite angles of parallelogram are equal
Answer:
6x+50
Step-by-step explanation:
we need to distribute the 5 first
5x+50+x
then
6x+50
Answer:
-43
Step-by-step explanation:
-(7)+6(-6)
-7-36
-43
Answer:
D
Step-by-step explanation:
We have to find the vertex of m(t) = t² - 4t + 25
a = 1
b = 4
c = 25
To do that we first need to move the 25 to the other side by subtracting 25 from both sides
m(t) = t² - 4t + 25
- 25 - 25
m(t) - 25 = t² - 4t
To continue completing the square, we have to add 4 to both sides since it is the square of half of b.
m(t) - 25 + 4 = t² - 4t + 4
m(t) - 21 = t² - 4t + 4
Now, we already found the minimum amount of members, but let's finish the square completion to find the vertex.
m(t) - 21 = t² - 4t + 4
Factor the right side
m(t) - 21 = (t-2)(t-2)
m(t) - 21 = (t-2)²
Finish it by adding 21 to both sides
m(t) - 21 = (t-2)²
+ 21 +21
m(t) = (t-2)² + 21
With this vertex form equation, we can tell that the vertex is (2,21)
Meaning 21 is the lowest number for m(t) for this equation.
Answer:
(-1, -1) Let me know if the explanation didn't make sense.
Step-by-step explanation:
If we graph the three points we can see what looks like a quadrilateral's upper right portion, so we need a point in the lower left. This means M is only connected to N here and P is only connected to N. So we want to find the slope of these two lines.
MN is easy since their y values are the same, the slope is 0.
NP we just use the slope formula so (y2-y1)/(x2-x1) = (-1-3)/(5-4) = -4.
So now we want a line from point M with a slope of -4 to intersect with a line from point P with a slope of 0. To find these lines weuse point slope form for those two points. The formula for point slope form is y - y1 = m(x-x1)
y-3 = -4(x+2) -> y = -4x-5
y+1 = 0(x-5) -> y = -1
So now we want these two to intersect. We just set them equal to each other.
-1 = -4x -5 -> -1 = x
So this gives us our x value. Now we can plug that into either function to find the y value. This is super easy of we use y = -1 because all y values in this are -1, so the point Q is (-1, -1)