Answer:
The proof contains a simple direct proof, wrapped inside the unnecessary logical packaging of a proof by contradiction framework.
Step-by-step explanation:
The proof is rigourous and well written, so we discard the second answer.
This is not a fake proof by contradiction: it does not have any logical fallacies (circular arguments) or additional assumptions, like, for example, the "proof" of "All the horses are the same color". It is factually correct, but it can be rewritten as a direct proof.
A meaningful proof by contradiction depends strongly on the assumption that the statement to prove is false. In this argument, we only this assumption once, thus it is innecessary. Other proofs by contradiction, like the proof of "The square root of 2 is irrational" or Euclid's proof of the infinitude of primes, develop a longer argument based on the new assumption, but this proof doesn't.
To rewrite this without the superfluous framework, erase the parts "Suppose that the statement is false" and "The fact that the statement is true contradicts the assumption that the statement is false. Thus, the assumption that the statement was false must have been false. Thus, the statement is true."
The answer is ..........2/3
Answer:
The probability that the restaurant can accommodate all the customers who do show up is 0.3564.
Step-by-step explanation:
The information provided are:
- At 7:00 pm the restaurant can seat 50 parties, but takes reservations for 53.
- If the probability of a party not showing up is 0.04.
- Assuming independence.
Let <em>X</em> denote the number of parties that showed up.
The random variable X follows a Binomial distribution with parameters <em>n</em> = 53 and <em>p</em> = 0.96.
As there are only 50 sets available, the restaurant can accommodate all the customers who do show up if and only if 50 or less customers showed up.
Compute the probability that the restaurant can accommodate all the customers who do show up as follows:
![P(X\leq 50)=1-P(X>50)\\=1-P(X=51)-P(X=52)-P(X=53)\\=1-[{53\choose 51}(0.96)^{51}(0.04)^{53-51}]-[{53\choose 52}(0.96)^{52}(0.04)^{53-52}]\\-[{53\choose 53}(0.96)^{53}(0.04)^{53-53}]\\=1-0.27492-0.25377-0.11491\\=0.3564](https://tex.z-dn.net/?f=P%28X%5Cleq%2050%29%3D1-P%28X%3E50%29%5C%5C%3D1-P%28X%3D51%29-P%28X%3D52%29-P%28X%3D53%29%5C%5C%3D1-%5B%7B53%5Cchoose%2051%7D%280.96%29%5E%7B51%7D%280.04%29%5E%7B53-51%7D%5D-%5B%7B53%5Cchoose%2052%7D%280.96%29%5E%7B52%7D%280.04%29%5E%7B53-52%7D%5D%5C%5C-%5B%7B53%5Cchoose%2053%7D%280.96%29%5E%7B53%7D%280.04%29%5E%7B53-53%7D%5D%5C%5C%3D1-0.27492-0.25377-0.11491%5C%5C%3D0.3564)
Thus, the probability that the restaurant can accommodate all the customers who do show up is 0.3564.
Answer:
75%
Step-by-step explanation:
3/4=7.5
