The answer would be 1,300 I think I don’t know tbh
If you mean: (√(16r)^6 that is the same as:
(16r)^(1/2)^6
relevant rule: (a^b)^c=a^(b*c), in this case
(16r)^(6*1/2)
(16r)^3
4096r^3
Ok so there are no real solutions for xy=15000 and x+y=5
there are immaginary solutions though so
xy=15000
x+y=5
x+y=5
y=5-x
x(5-x)=15000
-x^2+5x=15000
0=x^2-5x+15000
quadriacic formula
if ax^2+bx+c=0, then
x=

x^2-5x+15000
a=1
b=-5
c=15000
x=

x=

x=

x=

so the numbers are

and