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2 years ago

Square root of 16r raised to the 6

1 answer:

7 0

If you mean: (√(16r)^6 that is the same as:

(16r)^(1/2)^6

relevant rule: (a^b)^c=a^(b*c), in this case

(16r)^(6*1/2)

(16r)^3

4096r^3

You might be interested in

Bag A contains 3 red balls and 3 blue balls.

dezoksy [38]

Answer:

30% probability that the ball taken from B is red.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question:

Red ball from urn A:

3/6 = 1/2 probability of getting a red ball from urn A.

Then urn B will have 5 balls, 2 of which are red, so 2/5 probability of getting a red ball.

Blue ball from urn A:

3/6 = 1/2 probability of getting a blue ball from urn A.

Then urn B will have 5 balls, 1 of which is red, so 1/5 probability of getting a red ball.

Total:

$p = \frac{1}{2}*\frac{2}{5} + \frac{1}{2}*\frac{1}{5} = \frac{2}{10} + \frac{1}{10} = \frac{3}{10}$

3/10 = 0.3 = 30%.

30% probability that the ball taken from B is red.

4 0

3 years ago

There are 3 islands A,B,C. Island B is east of island A, 8 miles away. Island C is northeast of A, 5 miles away and northwest of

Nostrana [21]

Answer:

The bearing needed to navigate from island B to island C is approximately 38.213º.

Step-by-step explanation:

The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:

$AC^{2} = AB^{2}+BC^{2}-2\cdot AB\cdot BC\cdot \cos \theta$ (1)

Where:

$AC$ - The distance from A to C, measured in miles.

$AB$ - The distance from A to B, measured in miles.

$BC$ - The distance from B to C, measured in miles.

$\theta$ - Bearing from island B to island C, measured in sexagesimal degrees.

Then, we clear the bearing angle within the equation:

$AC^{2}-AB^{2}-BC^{2}=-2\cdot AB\cdot BC\cdot \cos \theta$

$\cos \theta = \frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC}$

$\theta = \cos^{-1}\left(\frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC} \right)$ (2)

If we know that $BC = 7\,mi$ , $AB = 8\,mi$ , $AC = 5\,mi$ , then the bearing from island B to island C:

$\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]$

$\theta \approx 38.213^{\circ}$

The bearing needed to navigate from island B to island C is approximately 38.213º.

8 0

2 years ago

Graph the line whose x-intercept is 8 and whose y-intercept is -9.

eduard

Answer: attached image

7 0

1 year ago

Solve the equation and check your solution for -14=k+6

andrew11 [14]

Answer:

-20=k

Step-by-step explanation:

-14=k+6

-6 -6

-20=k

-14=-20+6

-14=-14

5 0

2 years ago

Liz flips a coin 60 times. The coin lands heads up 36 times and tails up 24 times. The EXPERIMENTAL probability of the coin land

malfutka [58]

Answer:

60%

Step-by-step explanation:

36 = heads

36/60 = 60%

3 0

2 years ago

Read 2 more answers