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Nataly_w [17]
3 years ago
5

HELP Me PLEASE BUT I JUST NEED THE ANSWER AND I hAVE 35MORE QUESTINS

Mathematics
1 answer:
iren [92.7K]3 years ago
6 0
<h2>Answer:</h2>

<u>The length is</u><u> 12 feet</u>

<h2>Step-by-step explanation:</h2>

The width of the garden is 5 feet

After that the total edging is telling us the area

We know that

<h3>Area of rectangle = length x width</h3>

So

60 = length x 5

Length = 60 / 5

Length = 12 feet

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When a trend line is drawn on a scatterplot, there are 4 points above the trend line. About how many points should be below the
scoundrel [369]
There is no exact rule for lines of best fit. However, in general, there should be roughly the same amount above as below. So, if we are following this rule, there should be about 4 below as well. 
5 0
3 years ago
Read 2 more answers
A University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students. A s
Alla [95]

Answer:

The point estimate for this problem is 0.48.

Step-by-step explanation:

We are given that a University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students.

A survey of 2,800 students was conducted and the students were asked if they felt comfortable reporting cheating by their fellow students. The results were 1,344 answered "Yes" and 1,456 answered "no".

<em>Let </em>\hat p<em> = proportion of students who felt comfortable reporting cheating by their fellow students</em>

<u></u>

<u>Now,  point estimate (</u>\hat p<u>) is calculated as;</u>

                               \hat p=\frac{X}{n}

where, X = number of students who answered yes = 1,344

            n = number of students surveyed = 2,800

So, Point estimate (\hat p)  =  \frac{1,344}{2,800}

                                     =  <u>0.48 or 48%</u>

5 0
3 years ago
A welder requires 18 hours to do a job. After the welder and an apprentice work on a job for 6 hours, the welder moves to anothe
Dafna1 [17]

Answer:

the apprentice can complete the job in 30 hours by working alone.

Step-by-step explanation:

Given:

Number of hours required to complete a job by welder = 18 hours

Number of hours welder work on job = 6 hours.

Number of hours required by apprentice to complete the job = 14 hours

We need to find Number of hours required to complete a job by apprentice alone.

Solution:

Let Number of hours required to complete a job by apprentice alone be 'a'.

Also let the job completed be = 1

Now we know that ;

Time required on job is equal to sum of Number of hours welder work on job and Number of hours required by apprentice to complete the job.

framing in equation form we get

Time required on job =  6+14 =20\ hrs

Now we can say that;

each has done a fraction of the work so we will add to two fraction as number of hours of work done by Total number of hours required to do the work to complete 1 job.

so we can frame the equation as;

\frac{6}{18}+\frac{20}{a}=1

By reducing the fraction we get;

\frac{1}{3}+\frac{20}{a}=1

Now we will make the denominator common to solve the fraction we get;

\frac{1\times a}{3\times a}+\frac{20\times3}{a\times3}=1\\\\\frac{a}{3a}+\frac{60}{3a}=1

Now denominators are same so we will solve the numerator we get;

\frac{a+60}{3a}=1

Multiplying both side by 3a we get;

\frac{a+60}{3a}\times3a=1\times 3a\\\\a+60=3a

Combining the like terms we get;

3a-a=60\\\\2a=60

Dividing both side by 2 we get;

\frac{2a}{2}=\frac{60}{2}\\\\a=30\ hrs

Hence the apprentice can complete the job in 30 hours by working alone.

4 0
3 years ago
Assume that k and V0 are constant and are, respectively, 0.02, and 7. The parameter CA varies from an initial value CA0 = 100 to
julia-pushkina [17]

Answer:

V = 929.7

Step-by-step explanation:

Given the equation:

\frac{dCA}{dV} = \frac{-kCA}{V0}

The integral of the above equation is:

\int\limits {\frac{dCA}{dV} } = \int\limits{\frac{-kCA}{V0} }

Re-organizing the integrals:

\int\limits  {\frac{dCA}{CA} } = \int\limits {\frac{-kdV}{V0} }

Integrating:

ln(CA) - ln(CA0) = \frac{-kV}{V0}

Inputting the initial conditions of CA and the values of k and V0:

ln(7) - ln(100) = \frac{-0.02V}{7}

1.946 - 4.605 = -0.00286V

-2.659 = -0.00286V

=> V = \frac{2.659}{0.00286}

V = 929.720

Approximating to one decimal place,

V = 929.7

7 0
3 years ago
0.09859154929 round to nearest tenth
Free_Kalibri [48]

Answer:

0.1

Step-by-step explanation:

5 0
3 years ago
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