Answer:
The first, second, and fifth statements are correct.
Step-by-step explanation:
We are given a circle with the equation:

And we want to select the statements that are true.
First, we can convert the equation into standard form. We can group each variable:

And complete the square for the first term:

Factor and simplify:

We can rewrite our equation as:

So, this tells us that we have a circle centered on (1, 0) with a radius of 3 units.
In this case, the first statement, second statement (the point (1,0) is on the x-axis), and fifth statements are correct (the square root of 9 is also 3).
Answer:
62 degrees
Step-by-step explanation:
Since lines i and k are parallel, angle b and h are interior angles and are equal to each other. Set up the equation by setting the two equal to each other.
8x-34=5x+2
Subtract 5x from both sides. (it cancels on the right side)
3x-34=2
Add 34 to both sides. (cancels on the left side)
3x=36
Divide both sides by 3.
x=12
Now plug it into either equation since they are equal. I'm gonna use the one for angle h so that it's less confusing.
5(12)+2
60+2
62
The measure of angle h is 62 degrees.
Answer:
8000
Step-by-step explanation:
Area of floor=25×20m
=500²
Area of each tile=area if each rhombus
=25×25=625cm²
No. of tiles required= area of floor/ area of each tile
=500×104⁴/ 625
=4/5 ×10×1000
=8000
hope it helps!
Answer:
3) (2,-9)
4) (0,-5)
5) (1,-8)
Step-by-step explanation:
3)
The vertex will occur between you x-intercepts.
You already found that happens at x=2.
To find the corresponding y-coordinate, replace x in
f(x)=(x+1)(x-5) with 2:
f(2)=(2+1)(2-5)
f(2)=(3)(-3)
f(2)=-9
So the vertex is (2,-9).
4)
The y-intercept is when x=0.
So in f(x)=(x+1)(x-5) replace x with 0:
f(0)=(0+1)(0-5)
f(0)=(1)(-5)
f(0)=-5
So the y-intercept is (0,-5).
5)
To find another point just plug in anything besides any x already used.
We preferably want to use a value of x that will keep us on their grid however far up,down,left, or right their grid goes out. So I'm going to choose something close to the vertex which is at x=2. Let's go with x=1.
So replace x in f(x)=(x+1)(x-5) with x=1:
f(1)=(1+1)(1-5)
f(1)=(2)(-4)
f(1)=-8
So another point to graph is (1,-8).