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3 years ago

100 mL of 1.0 M formic acid (HCOOH) is titrated with 1.0 M sodium hydroxide (NaOh).

2 answers:

7 0

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Do you mean at a pH = pKa, what is the fraction?
pH = pKa + log(base)/(acid) 
4 = 4 + log (base)/(acid) 
(base)/(acid) = 1 
So 50% has been converted.

Bezzdna [24]3 years ago

7 0

Answer:

Fraction of carboxyl group that will have been converted to COO- = 50%

Explanation:

pKa of formic acid = 4

At pKa, titration is at equivalence point.

At equivalence point, number of moles of HCOOH undissociated is equal to number of moles of dissociated $(HCOO^-)$

$(HCOOH)_{eq}= (HCOO^-)_{eq}$

Thus, fraction of carboxyl group that will have been converted to COO-:

$\frac{[HCOO^-]_{eq}}{[HCOO^-]_{eq}+[HCOOH]_{eq}} \times 100 = \frac{[HCOO^-]_{eq}}{[HCOO^-]_{eq}+[HCOO^-]_{eq}}$

$\frac{[HCOO^-]_{eq}}{2[HCOO^-]_{eq}} \times 100 = 50 \%$

fraction of carboxyl group that will have been converted to COO- = 50%

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jeyben [28]

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3 years ago

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4 years ago

For a typical titration, 0. 010 m naoh is the titrant (in the buret). if the initial buret reading is 2. 45 ml, and the final bu

pickupchik [31]

16.25 ml NaOH was used for the titration.

<h3>Titration:</h3>

"The process of calculating the quantity of a material A by adding measured increments of substance B, the titrant, with which it reacts until exact chemical equivalency is obtained (the equivalence point)" is the definition of titration.

A titration is a method for figuring out the concentration of an unknown solution by using a solution with a known concentration. Until the reaction is finished, the titrant (the known solution) is typically added from a buret to a known volume of the analyte (the unknown solution).

0. 010 m NaOH is the titrant (in the buret).

The initial buret reading is 2. 45 ml

The final buret reading is 18. 70 ml

The volume of NaOH = 18.70ml - 2.45 ml

= 16.25 ml

Therefore, 16.25 ml NaOH was used for the titration.

Learn more about titration here:

brainly.com/question/27107265

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1 year ago

If the pH of the solution is 10, what is the [OH-] concentration?

swat32

Answer:

1× $10^{-4}M$

Explanation:

To solve this, you will need to do multiple steps.

Firstly, you will have to convert to pOH from pH, which is done by simply subtracting 14-10 to get a pOH of 4.

Then, use the following formula to calculate the [OH-} concentration:

[OH-]= $10^{-pOH}$

When converted to Scientific Notation, you get a resulting answer of

1× $10^{-4}M$ .

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3 years ago

Write the recation of formation of ions by fluorine and potassium

bekas [8.4K]

Answer: The reaction of formation of ions by fluorine and potassium is $K^{+} + F^{-} \rightarrow KF$ .

Explanation:

Atomic number of potassium is 19 and its electronic distribution is 2, 8, 8, 1. So, in order to attain stability it needs to lose 1 electron due to which it forms $K^{+}$ ion.

Atomic number of fluorine is 9 and its electronic distribution is 2, 7. In order to attain stability it needs to gain one electron and hence forms $F^{-}$ ion.

Therefore, when both these ions come in contact with each other then it leads to the formation of KF compound.

The reaction equation for this is as follows.

$K^{+} + F^{-} \rightarrow KF$

Thus, we can conclude that the reaction of formation of ions by fluorine and potassium is $K^{+} + F^{-} \rightarrow KF$ .

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3 years ago