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netineya [11]
4 years ago
11

A student has 5 mL of 0.300 M (NH4)2CrO4 solution. What is the concentration of NH4+ in this solution?

Chemistry
1 answer:
mixer [17]4 years ago
4 0
The answer is 0.600 M; but I don't know how to get to that answer.
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Did democritus belive atoms retain there identity as a chemical reaction
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No He believed tiny particles were invisible and couldn't be changed....So No The person that believed in this was Dalton .
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3 years ago
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If you have nitrate and carbon oxygen what can that combine with to make
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Answer: Gunpowder

Explanation:

Gunpowder is made by mixing potassium nitrate with two fuels (atoms that can combine with oxygen atoms and release energy), carbon (charcoal) and sulfur. The oxygen atoms leave the nitrates and move onto the carbon and sulfur atoms, releasing a buttload of energy.

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Which of these statement(s) is/are true about a balloon filled with 1.00 mol N2 (g) at STP?
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Answer:

I. The balloon has a volume of 22.4L

III. The balloon contains 6.022x10^23 molecules.

Explanation:

At stp, it has been proven that 1mole of a gas occupy 22.4L.

Therefore, option (i) is correct.

The molar mass N2 = 14.01 x 2 = 28.02g/mol

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Mass of N2 =..?

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Mass of N2 = 1 x 28.02 = 28.02g.

The mass content of the balloon is 28.02g, therefore, option (ii) is wrong.

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 molecules. This implies that 1 mole of N2 also contains 6.02x10^23 molecules

Therefore, option (iii) is correct.

The correct options to the question are:

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3 years ago
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Removing the tip of the stem in a young plant will most directly interfere with the production of
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c.

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3 years ago
Bromine has a density of 3.10g/cm3. If you have 50.0 ML of bromine, how many grams do you have?
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The answer is

<h2>155 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of bromine = 50 mL

density = 3.10 g/cm³

It's mass is

mass = 50 × 3.10

We have the final answer as

<h3>155 g</h3>

Hope this<u> </u>helps you

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