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4 years ago

Can somebody help me with midpoints in geometry for 15 points?

Mathematics

2 answers:

Goryan [66]4 years ago

8 0

I can help. I know a thing or two

jekas [21]4 years ago

3 0

This may help. midpoint was the easiest for me

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1.write the equations of three lines whose graphs are parallel to one another . 2.write the equation of two lines whose graphs a

Arlecino [84]

Y = -2x + 1
y = -2x + 2
y = -2x + 3
these are all parallel lines because they have the same slopes (-2) but different y intercepts.

y = 3x + 4
y = -1/3x + 3
these are perpendicular lines because they have negative reciprocal slopes.

slope of a line parallel to the x axis : If it is parallel to the x axis, it is a horizontal line and has a slope of 0.

slope of a line perpendicular to the x axis : if it is perpendicular to the x axis, it is a vertical line with a slope that is undefined.

slope of line parallel to the y axis : vertical line, undefined slope

slope of a line perpendicular to the y axis : horizontal line, slope of 0

6 0

4 years ago

Read 2 more answers

I don't understand which selection it would be for each.

Vladimir79 [104]

Answer:

ThEy WoUlD Be I D K

Step-by-step explanation:

5 0

3 years ago

2. Ryan has nine 14-ounce bags of popcorn

Serjik [45]

Answer:

Step-by-step explanation:

9 times 14 equals 126

126 divided by 3 equals 42

3 0

4 years ago

I just need help with it all I don't know really what to do

Orlov [11]

Answer:

Step-by-step explanation:

3 0

4 years ago

A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes

Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is $\dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}$

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

$A = \dfrac{7}{4} \cdot a^2 \cdot cot \left (\dfrac{180 ^{\circ}}{7} \right )$

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

$\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}$

$s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69$

$The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52$

The area of the heptagon MNSRQPO is therefore;

$A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94$

$MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times 21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08$

By sine rule, we have

$\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}$

$sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})$

$\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}$

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

$Area \ of \Delta MSQ = \dfrac{1}{2} \times 43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}$

The area of the of the garden plated with flowers, $A_{req}$ , is given as follows;

$A_{req}$ = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

$A_{req}$ = 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, $A_{req}$ ≈ <u>923.558 m²</u>

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0

3 years ago