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vekshin1
4 years ago
15

2. Ryan has nine 14-ounce bags of popcorn

Mathematics
1 answer:
Serjik [45]4 years ago
3 0

Answer:

42

Step-by-step explanation:

9 times 14 equals 126

126 divided by 3 equals 42

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Find the next two numbers in the sequence 5,2,-1,…
Nataly_w [17]

Answer:

The answer is (-4) and (-7).

Step-by-step explanation:

<h3><u>Given</u>;</h3>
  • a₁ = 5
  • a₂ = 2
  • a₃ = (-1)
<h3><u>To </u><u>Find</u>;</h3>
  • a₄ = ?
  • a₅ = ?
<h3><u>Formula</u>;</h3>
  • aₙ = a + (n – 1) × d

Now, for common difference (d)

d = a₂ – a₁ = 2 – 5 = -3

d = a₃ – a₂ = (-1) – 2 = -3

Here, common difference is same everywhere.

So, for fourth term or n = 4

aₙ = a + (n – 1) × d

a₄ = 5 + (4 – 1) × (-3)

a₄ = 5 + 3 × (-3)

a₄ = 5 – 9

a₄ = -4

Then, for fifth term or n = 5

a₅ = 5 + (5 – 1) × (-3)

a₅ = 5 + 4 × (-3)

a₅ = 5 – 12

a₅ = -7

Thus, The fourth term is (-4) and fifth term is (-7).

5 0
2 years ago
A city is located at an elevation that is below sea level. what is a possible elevation for that city
HACTEHA [7]
Well it could be anything negative, for example maybe -34 below sea level.
6 0
4 years ago
Read 2 more answers
Let A(t)A(t) be the area of a circle with radius r(t)r(t), at time tt in min. Suppose the radius is changing at the rate of drdt
torisob [31]

Answer:

At a point when r = 6 ft

The rate of change of Area with time is given as

(dA/dt) = 36π = 113.1 ft²/min

Step-by-step explanation:

Area of a circle, A = πr²

A = πr²

(dA/dt) = (dA/dr) × (dr/dt)

(dA/dr) = 2πr, (dr/dt) = 3

(dA/dt) = 2πr × 3 = 6πr

At a point when r = 6 ft

(dA/dt) = 6πr = 6π × 6 = 36π = 113.1 ft²/min

6 0
3 years ago
Plz help plz ASAP plz help
romanna [79]

Answer:

10.4 meters

Step-by-step explanation:

3² + 10² = c²

9 + 100 = c²

c² = 109

c = √109 ≈ 10.4

8 0
3 years ago
Write number 0.0082 in scientific notation​
Ede4ka [16]

Answer: 8.2×10^-3

Move the decimal over three places to eliminate unnecessary numbers (0s). Since you are moving the decimal to the right it will be 10 to a negative number.

8 0
3 years ago
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