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3 years ago

Can someone please help me understand this

Mathematics

1 answer:

Lorico [155]3 years ago

8 0

Answer:

No, because one x-value corresponds to two different y-values.

Step-by-step explanation:

Given a function where x represents an input of a particular value, which gives an output for that particular value inputted as defined by the function, if the function is true and valid, a particular value of input should not give us different values of output.

Thus, from the table given, at x = 5, we have y = 3.

Also, at x = 5, we have y = 2.

Here, one x-value is given us two different y-values. This is not true if a function. We cannot regard the table given as representing a function.

Therefore, the answer is:

No, because one x-value corresponds to two different y-values.

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Function or not a function

dalvyx [7]

Answer:

Step-by-step explanation:

one x should only have one y for it to be a function

8 0

3 years ago

2. Four pieces of candy are drawn at random from a bag containing five orange pieces and seven brown pieces.

alexandr402 [8]

Answer:

a) $12C4 = \frac{12!}{4! (12-4)!}= \frac{12!}{4! 8!}=\frac{12*11*10*9*8!}{4! 8!}= 495$ ways

b) $5C2 = \frac{5!}{2! (5-2)!}= \frac{5!}{2! 3!}=\frac{5*4*3!}{2! 3!}= 10$ ways

c) $7C2 = \frac{7!}{2! (7-2)!}= \frac{7!}{2! 5!}=\frac{7*6*5!}{2! 5!}= 21$ ways

Step-by-step explanation:

Combinatory means combination or arrangement of different elements.

If we have n total elements and we want to find in how many ways we can select x we can use this general formula:

$nCx= \frac{n!}{x! (n-x)!}$

Where $n! = n *(n-1)!$

a. How many different ways can four pieces be selected from the 12 colored pieces?

For this case we have:

$12C4 = \frac{12!}{4! (12-4)!}= \frac{12!}{4! 8!}=\frac{12*11*10*9*8!}{4! 8!}= 495$ ways

b. How many different ways can two orange pieces be selected from five orange pieces?

For this case we have:

$5C2 = \frac{5!}{2! (5-2)!}= \frac{5!}{2! 3!}=\frac{5*4*3!}{2! 3!}= 10$ ways

c. How many different ways can two brown pieces be selected from seven brown pieces?

For this case we have:

$7C2 = \frac{7!}{2! (7-2)!}= \frac{7!}{2! 5!}=\frac{7*6*5!}{2! 5!}= 21$ ways

6 0

4 years ago

I have been stuck on this question for a while plz help

ahrayia [7]

The median of the data in the box plot is 6.

The first quartile is 5.5 (median of first half of data set)
The third quartile is 7 (median of upper half of data set)
The lower extreme is 3.5 (lowest number in the data set)
The upper extreme is 7.5 (highest number in the data set)

3 0

3 years ago

Please help with 1,2, and 3

Brilliant_brown [7]

1)He should measure the perimeter.
9+5+9+5=28 inches
2) she should measure the circumference
3) He should measure the Area
8×14=112 Square feet

6 0

3 years ago

at dinner you order a meal that costs $16.00 what is the total cost of the meal after a 20% tip and sales tax of 8%

Taya2010 [7]

20% = 3.20
8%=1.28
28%=4.48+16=20.48
The total cost would be $20.48

7 0

3 years ago

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