Question

I have class in a half an hour and I still haven't solved all of the hw questions... please help guys I'll give 90 points and brainliest for the first correct answer with brief explanation: thank you SOOOOOOOOOO much!
Given: E, F, Q, D∈k(O),O ∈ ED, m∠DFQ = 10°, measure of arc EF = 28° Find: Angles of △EFQ

Answer 1

Answer:

Angles of △EFQ:

m<EFQ = 100°

m<EQF = 14°

m<FEQ = 66°

Step-by-step explanation:

ED is the diameter of the circle O

so m<EFD = 1/2 (180) = 90°

Given m∠DFQ = 10°

△EFQ

m<EFQ = m<EFD + m∠DFQ = 10° + 90° = 100°

arc EF = 28°,

so m<EQF = 1/2 (28) = 14°

m<FEQ = 180 - ( 100° +  14°) = 66°

Answer:

m<EFQ = 100°

m<EQF = 14°

m<FEQ = 66°