Answer: 92
Step-by-step explanation:
Alrighty
squaer base so length=width, nice
v=lwh
but in this case, l=w, so replace l with w
V=w²h
and volume is 32000
32000=w²h
the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW
alrighty
we gots
SA=W²+4HW and
32000=W²H
we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute
SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W
take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?
0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W
so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H
the box is 20cm height and the width and length are 40cm
Step 1: 6x - 2x - 5 = -6 + 21
Step 2: 6x - 2x - 5 = 15
Step 3: 4x - 5 = 15
The next step would be to add 5 to both sides of the equation.
so Step 3: 4x - 5 = 15 .......add 5 to both sides would make
Step 4: 4x = 20
So after the next step you would have 4x = 20
Hope this helps! :)
(3x-5)+(x+1)=180
x=46
3(46)-5=133
m
To solve for a number x,
3x+4x-2=15
7x-2=15
7x=17
x=2 3/7
or x=~2.43
was one of your answer choices either of the first two equations?
