Answer:![a_0=25](https://tex.z-dn.net/?f=a_0%3D25)
Step-by-step explanation:
It is given that, ![(5x)^2=a_0x^2](https://tex.z-dn.net/?f=%285x%29%5E2%3Da_0x%5E2)
We need to find the value of ![a_0](https://tex.z-dn.net/?f=a_0)
As ![(5x)^2=a_0x^2](https://tex.z-dn.net/?f=%285x%29%5E2%3Da_0x%5E2)
Solving LHS
![25x^2=a_0x^2](https://tex.z-dn.net/?f=25x%5E2%3Da_0x%5E2)
Now comparing the coefficients of ![x^2](https://tex.z-dn.net/?f=x%5E2)
In LHS the coefficient of
is 25
In RHS the coefficient of
is ![a_0](https://tex.z-dn.net/?f=a_0)
It implies that, ![a_0=25](https://tex.z-dn.net/?f=a_0%3D25)
So, the value of
is 25.
Answer:
Step-by-step explanation:
1 <em>4(1) + 2 6</em>
3 <em>4(3) + 2 14</em>
6 <em>4(6) + 2 26</em>
0 <em>0 + 3 3</em>
2 <em>2 + 3 5</em>
4 <em>4 + 3 7</em>
<em>1 1 - 1 </em> 0
<em>3 3 - 1</em> 2
<em>5 5 - 1</em> 4
7.) 4x greater because 8*8=64 and 4*4=16 64/16=4
8.) 22 because 70-13-13=44/2=22
9.) 32 because the square root of 64 is 8 so each side is 8 square feet
10.) The rectangle is an 8 by 5 and the perimeter is 26
Answer:
Yes they are.
Because:
As said in the rules you have to keep the bases and add the exponents.
Answer:
c
Step-by-step explanation:
because the real awnser is 57/4 but simpfly