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2 years ago

3x – 2y = -11 and 5x + y =-1?'

Mathematics

1 answer:

Grace [21]2 years ago

7 0

Answer:

2x + 3y

Step-by-step explain

5x - 3x = 2x

2y + (1)y = 3y

2x + 3y

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Solve, show all four steps.

Eva8 [605]

3x-6+10x+15=35
10x+3x=35-15+6
13x=26
x=2

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2 years ago

Solve the absolute value equation and enter the solution in set notation.<br><br> |2x−3|−7=0

ziro4ka [17]

Answer:

The solutions are −5 and 1 .

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2 years ago

Select from the drop-down menus to correctly identify whether the given operation is closed or not closed with respect to each s

Tatiana [17]

Answer:

Real numbers are "closed" under multiplication

Irrational numbers are "not closed" under division

Integers are "closed" under subtraction

Positive ration numbers are "closed"

Hope this helps! :)

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2 years ago

) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv$

$=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}$

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3 years ago

Find the area of the trapezoid.

riadik2000 [5.3K]

Answer:

Step-by-step explanation:

(Top bottom plus bottom bottom )× height divided by 2

(4+6)*6÷2=36

5 0

2 years ago

Read 2 more answers