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3 years ago

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For the following exercise, determine the range (possible values) of the random variable, . Wood paneling can be ordered in thic

knesses of 1/16, 1/8, or 3/16 inch. The random variable is the total thickness of paneling in two orders.

1 answer:

dedylja [7]3 years ago

3 0

Answer:

Range = 0.125

Step-by-step explanation:

The detailed steps is as shown in the attached file.

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Step-by-step explanation:

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3 years ago

Read 2 more answers

FUNCTIONS: In the space provided, type the answer in descending order as it applies without any spaces between the letters, numb

Aleonysh [2.5K]

Answer:

Hence The composition $(fog)(x)$ of the given function is $x^2+12x+29$ .

Step-by-step explanation:

Given:

$f(x) = x^2+2x-6$

$g(x)=x+5$

We need to find $(f o g)(x)$ .

Solution:

Now we can say that;

$(f o g)(x)$ = $f(g(x))$

$(fog)(x) = (x+5)^2+2(x+5)-6$

Now Applying distributive property we get;

$(fog)(x) = (x+5)^2+2\times x+2\times5-6\\\\(fog)(x) = (x+5)^2+2x+10-6\\\\(fog)(x) = (x+5)^2+2x+4$

Now Solving the exponent function we get;

$(fog)(x) = x^2+2\times x\times 5+5^2+2x+4\\\\(fog)(x) = x^2+10x+25+2x+4\\\\(fog)(x) = x^2+12x+29$

Hence The composition $(fog)(x)$ of the given function is $x^2+12x+29$ .

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3 years ago