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Kitty [74]
3 years ago
11

In order to join an online learning community there is a $20 start up fee and a $5 monthly fee write an equation in slope interc

ept form that Models this situation
Mathematics
1 answer:
faust18 [17]3 years ago
6 0
100 20 x 5 Try That!!
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Elliot borrowed $3800 from the bank for 3 years at a 4.25% simple interest rate?
Ipatiy [6.2K]

$161.50

Step-by-step explanation:

4.25% of $3800 is $161.50

3 0
3 years ago
Help please!! if it’s correct ill mark you as brainliest
Levart [38]

Answer:

\frac{2\pi }{25}

(8^2 x pi)/ (20x40)

6 0
3 years ago
What's the area of a square picture with 16 inch sides
Vikentia [17]
To find the area of a square picture with 16 inch sides, we must use the formula for the area of a square: A=s^2, where s represents the value of the side length of the square.  

To solve, we must plug in the given side length of 16 inches into the formula.

A = (16 inches)^2
A= 256 inches^2

Therefore, your answer is 256 inches^2.  

Hope this helps!
7 0
4 years ago
Read 2 more answers
Joe flipped a coin 100 times. It landed heads
gayaneshka [121]

Answer:

48%

Step-by-step explanation:

48 out of 100 = 48%

:D

6 0
3 years ago
Read 2 more answers
Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =
irga5000 [103]

Answer:  The required solution is y=50e^{0.1386t}.

Step-by-step explanation:

We are given to solve the following differential equation :

\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

\dfrac{dy}{y}=kdt.

Integrating both sides, we get

\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]

Also, the conditions are

y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50

and

y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.

Thus, the required solution is y=50e^{0.1386t}.

8 0
3 years ago
Read 2 more answers
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