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3 years ago

11

In order to join an online learning community there is a $20 start up fee and a $5 monthly fee write an equation in slope interc

ept form that Models this situation

1 answer:

faust18 [17]3 years ago

6 0

100 20 x 5 Try That!!

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Elliot borrowed $3800 from the bank for 3 years at a 4.25% simple interest rate?

Ipatiy [6.2K]

$161.50

Step-by-step explanation:

4.25% of $3800 is $161.50

3 0

3 years ago

Help please!! if it’s correct ill mark you as brainliest

Levart [38]

Answer:

$\frac{2\pi }{25}$

(8^2 x pi)/ (20x40)

6 0

3 years ago

What's the area of a square picture with 16 inch sides

Vikentia [17]

To find the area of a square picture with 16 inch sides, we must use the formula for the area of a square: A=s^2, where s represents the value of the side length of the square.

To solve, we must plug in the given side length of 16 inches into the formula.

A = (16 inches)^2
A= 256 inches^2

Therefore, your answer is 256 inches^2.

Hope this helps!

7 0

4 years ago

Read 2 more answers

Joe flipped a coin 100 times. It landed heads

gayaneshka [121]

Answer:

48%

Step-by-step explanation:

48 out of 100 = 48%

:D

6 0

3 years ago

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Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =

irga5000 [103]

Answer: The required solution is $y=50e^{0.1386t}.$

Step-by-step explanation:

We are given to solve the following differential equation :

$\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

$\dfrac{dy}{y}=kdt.$

Integrating both sides, we get

$\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]$

Also, the conditions are

$y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50$

and

$y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.$

Thus, the required solution is $y=50e^{0.1386t}.$

8 0

3 years ago

Read 2 more answers