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a_sh-v [17]
3 years ago
10

The graph of the equation y=12x−3 Determine the value of y for the point (4, y).

Mathematics
2 answers:
photoshop1234 [79]3 years ago
5 0

Answer:

y = 45

Step-by-step explanation:

Given that the x- coordinate of the point on the line is x = 4

To find the corresponding y- coordinate, substitute x = 4 into the equation.

y = 12x - 3 = (12 × 4) - 3 = 48 - 3 = 45

Thus the point is (4, 45 )

Novosadov [1.4K]3 years ago
4 0

Answer:

y=45

Step-by-step explanation:

y=12x-3

y=12(4)-3

y=45

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(7/8) of an hour is 52.5 minutes. If you are looking for half of that, it would be 26.25 minutes or 26 minutes and 15 seconds.
4 0
3 years ago
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Answer:

my answer is A. you only need substitute n from 1 to 4

3 0
3 years ago
OK this is another question which I need help on please please help if you can. CAUSED ME MUCH DISTRESS
r-ruslan [8.4K]

Answer:

15 = 2x - 3y

Step-by-step explanation:

We have the two points P1(3,-3) and P2(9,1).

First, calculate the slope between those points:

slope = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - (-3)}{9 - 3} = \frac{4}{6} = \frac{2}{3}

Now simply move 3 steps from (3,-3) towards the y-axis to get the intersection with the y-axis (each step reduces x by 1 and applies the slope to the y-value):

(3,-3)

---> (2, -3 - (2/3)) = (2,-3 2/3)

---> (1, (-3 2/3) - 2/3) = (1, -4 1/3)

---> (0, (-4 1/3) - 2/3) = (0,-5)

This tells us, that our line intersects the y-axis at (0,-5).

The general form of a line is f(x) = <SLOPE> * x + <Y-VALUEATXEQUALSZERO>.

In our case: f(x) = y = (2/3)x -5.

To get it into the correct form, we simply subtract y from both sides and get:

0 = (2/3)x - y - 5

To get only integers just multiply everything with 3 and add 15 and get:

15 = 2x - 3y, which fulfils the form asked for in the problem.

3 0
2 years ago
Which of the following describes the correct process for solving the equation 3x + 6 = 21 and arrives at the correct solution? (
Alja [10]

Answer:

d

Step-by-step explanation:

3x+6=21

-6+21= 15

15÷3=5

7 0
3 years ago
A publisher requires 2⁄3 of a page of advertisements for every 5 pages in a magazine. If a magazine has 98 pages, to the nearest
rjkz [21]

Let x be the number of pages of advertisements.

Write a proportion from the table:

\dfrac{2}{3} of a page of advertisment - 5 pages in a magazine

x pages of advertisment - 98 pages in a magazine,

then

\dfrac{\dfrac{2}{3}}{x}=\dfrac{5}{98}.

Find x:

x=\dfrac{\dfrac{2}{3}\cdot 98}{5}=\dfrac{196}{15}=13\dfrac{1}{13}.

Answer: 13 whole pages and \dfrac{1}{13} of 14th page are advertisments, so 14 pages contain advertisments.

3 0
3 years ago
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