Answer:
The product of 8x(5x−6) is 40x^2−48x
The product of (x−3)(5x−6) is 5x^2−21x+18
Step-by-step explanation:
<u><em>Verify each option</em></u>
Part 1) The product of 8x(5x−6) is 40x^2−48x
we have

Applying distributive property

Compare with the given value

therefore
The statement is true
Part 2) The product of −4x(2x2+1) is −8x^3−5x
we have

Applying distributive property

Compare with the given value

therefore
The statement is not true
Part 3) The product of (x−3)(5x−6) is 5x^2−21x+18
we have

Applying distributive property

Compare with the given value

therefore
The statement is true
Part 4) The product of (2x+3)(x^2+3x−5) is 2x^3+9x^2+9x−25
we have

Applying distributive property

Compare with the given value

therefore
The statement is not true
Answer: 1,278
Step-by-step explanation: 2(18x18)+2 1/2(18x14)
p.e.m.d.a.s. 18x18= 324 18x14= 252
2x324= 648 2.5x252=630
648+630 =1,278
Answer:
Yes
Step-by-step explanation:
1 hour = 60 min
25 hours = 60 x 25 min
These are two separate problems: in the first we will have to substitute in a new value for x into the original equation and in the second we will manipulate the preexisting equation for f(x).
To begin, we will sub in f(x/3). To do this, we will substitute each variable x in the equation (in this case there is only one) with x/3, and then simplify the resulting equation.
f(x) = 6x - 18
f(x/3) = 6(x/3) - 18
To simplify, we should distribute the 6 on the right side of the equation.
f(x/3) = 6x/3 - 18
Now, we can divide the first term on the right side to finalize our simplification.
f(x/3) = 2x -18
Secondly, we are asked to find f(x)/3. To do this, we will take our original value for f(x), and then simplify divide that entire function by 3.
f(x) = 6x - 18
f(x)/3 = (6x-18)/3
This means that we must divide each term of the binomial by 3, so we are really computing
f(x)/3 = 6x/3 - 18/3
We can simplify by dividing both of the terms.
f(x)/3 = 2x - 6
Therefore, your answer is that f(x/3) = 2x - 18, but f(x)/3 = 2x - 6. It is important to recognize that these are two similar, yet different, answers.
Hope this helps!