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elena55 [62]
3 years ago
14

Triangle XYZ is translated 4 units up and 3 units left to yield ΔX'Y'Z'. What is the distance between any two corresponding poin

ts on ΔXYZ and ΔX'Y'Z′
Mathematics
2 answers:
Paul [167]3 years ago
3 0

Answer:

The distance between any two corresponding points on ΔXYZ and ΔX'Y'Z′ is equal to 5\ units

Step-by-step explanation:

we know that

To find the distance, apply the Pythagoras Theorem

Let

x ----> the distance between any two corresponding points on ΔXYZ and ΔX'Y'Z′

x=\sqrt{4^{2}+3^{2}} \\ \\x=\sqrt{25}\ units\\ \\x=5\ units

vova2212 [387]3 years ago
3 0

Answer:

5

Step-by-step explanation:

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