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Inga [223]
4 years ago
7

Which expression represents the area of the base of the cone? A cone with diameter 12 inches, height 8 inches, and slant height

10 inches. B = pi r squared (pi) (5 squared) (pi) (6 squared) (pi) (10 squared) (pi) (12 squared)
Mathematics
1 answer:
Wewaii [24]4 years ago
8 0

Answer: (pi) (6 squared)

Step-by-step explanation:

Hi, the base area of a cone is a circle, so, to answer this question we have to apply the next formula:

Area of a circle: (pi) radius^2

The diameter (d) of a circle is equal to: 2 radius

So:

D = 2r

Replacing with the value given:

12 =2r

12/2=r

radius= 6 inches

Back with the Area formula:

A = (pi) 6^2

Feel free to ask for more if needed or if you did not understand something.  

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Read 2 more answers
The formula for the volume V of a cylinder is LaTeX: V=\pi r^2hV = π r 2 h, where r is the radius of the base anThe formula for
Alekssandra [29.7K]

Answer:

h = \frac{V}{\pi r^2}

h = 4 cm

Step-by-step explanation:

Volume of cylinder is given as V = \pi r^2 h

V is the volume the cylinder, r is its radius at the base, while is its height.

To select the formula for h (height) let's make h the subject of the formula as follows:

V = \pi r^2 h

\frac{V}{\pi r^2} = \frac{\pi r^2 h}{\pi r^2} (dividing both sides of the equation by \pi r^2 )

\frac{V}{\pi r^2} = h

h = \frac{V}{\pi r^2}

Use the formula above to find the height of the given cylinder where Volume (V) = 36π cm³, and base radius (r) = 3 cm:

h = \frac{36 \pi}{\pi 3^2} (substitution)

h = \frac{36 \pi}{\pi * 9}

h = \frac{36 \pi}{9 \pi}

h = \frac{36 \pi}{\pi * 9}

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8 0
3 years ago
Let f(x) = x2 − 2x − 3. The secant line through (2, f(2)) and (2 + h, f(2 + h)) for f(x) has slope h + 2. Use this formula to co
Mkey [24]

Answer:

a) slope of secant line = 3

b) slope of tangent line = 2

Step-by-step explanation:

Given:

- The function:

                           f(x) = x^2 -2*x - 3

- The slope for f(x) @ x = 2 is:

                           slope = h + 2

Find:

a) The slope of the secant line through (2, f(2)) and (3, f(3))

b) The slope of the tangent line at x = 2

Solution:

- Since we are given the slope of the line computed via secant method. All we need to do is evaluate the slope given for respective question.

- The slope of secant line between points ( 2 , f(2) ) and ( 3 , f(3) ) is:

                             slope = h + 2

Where,  h is the step size between two points. h = 3 - 2 = 1

                             slope = 1 + 2 = 3

Hence, the slope of the secant is 3.

- The slope of tangent line @ points ( 2 , f(2) ) is:

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Where,  h step size is reduced to infinitesimal small number. Hence, h = 0

                             slope = 0 + 2 = 2

Hence, the slope of the tangent is 2.

5 0
4 years ago
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