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lions [1.4K]
4 years ago
7

It cost three times as much to build a desk as it does to build a chair. if the total cost of building one desk and one chair is

$220, how much does it cost to build each?
Please show how you got your answer!!​
Mathematics
1 answer:
kogti [31]4 years ago
8 0

Answer:

vbgddddfgb

Step-by-step explanation:

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Hi, I need help.
slavikrds [6]

Answer:

B, 24 (second answer choice)

Step-by-step explanation:

4r+7s=23

r-2s=17

8r+14s=46

7r-14s=119

15r=165

r=11

11-2s=17..........by putting value of r in ii

-2s=17-11

2s= -6

s= -3

3r+3s=3*11+3(-3) you get this by putting values of r and s

       =33-9

       =24    (B)

7 0
3 years ago
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What best describes the expression y over 7? 7 times some number Some number minus 7 7 more than some number Some number divided
marysya [2.9K]
"Over" usually means divide. First hint, check.

If we write it out, it looks like this:

\frac{y}{7}

This is the same as <em>some number divided by 7.</em>
4 0
4 years ago
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What equation represents the proportional relationship displayed in the table? x 2 4 6 8 y 10 20 30 40 Enter your answer by fill
hjlf

Answer: y=5x

Step-by-step explanation:

pls mark brainliest :)

5 0
2 years ago
What is the product? (negative 3 s 2 t)(4 s minus t).
photoshop1234 [79]

Answer:

huh?

Step-by-step explanation:

5 0
2 years ago
PLEASE HELP 100 POINTS!!!!!!
horrorfan [7]

Answer:

A)  See attached for graph.

B)  (-3, 0)  (0, 0)  (18, 0)

C)   (-3, 0) ∪ [3, 18)

Step-by-step explanation:

Piecewise functions have <u>multiple pieces</u> of curves/lines where each piece corresponds to its definition over an <u>interval</u>.

Given piecewise function:

g(x)=\begin{cases}x^3-9x \quad \quad \quad \quad \quad \textsf{if }x < 3\\-\log_4(x-2)+2 \quad  \textsf{if }x\geq 3\end{cases}

Therefore, the function has two definitions:

  • g(x)=x^3-9x \quad \textsf{when x is less than 3}
  • g(x)=-\log_4(x-2)+2 \quad \textsf{when x is more than or equal to 3}

<h3><u>Part A</u></h3>

When <u>graphing</u> piecewise functions:

  • Use an open circle where the value of x is <u>not included</u> in the interval.
  • Use a closed circle where the value of x is <u>included</u> in the interval.
  • Use an arrow to show that the function <u>continues indefinitely</u>.

<u>First piece of function</u>

Substitute the endpoint of the interval into the corresponding function:

\implies g(3)=(3)^3-9(3)=0 \implies (3,0)

Place an open circle at point (3, 0).

Graph the cubic curve, adding an arrow at the other endpoint to show it continues indefinitely as x → -∞.

<u>Second piece of function</u>

Substitute the endpoint of the interval into the corresponding function:

\implies g(3)=-\log_4(3-2)+2=2 \implies (3,2)

Place an closed circle at point (3, 2).

Graph the curve, adding an arrow at the other endpoint to show it continues indefinitely as x → ∞.

See attached for graph.

<h3><u>Part B</u></h3>

The x-intercepts are where the curve crosses the x-axis, so when y = 0.

Set the <u>first piece</u> of the function to zero and solve for x:

\begin{aligned}g(x) & = 0\\\implies x^3-9x & = 0\\x(x^2-9) & = 0\\\\\implies x^2-9 & = 0 \quad \quad \quad \implies x=0\\x^2 & = 9\\\ x & = \pm 3\end{aligned}

Therefore, as x < 3, the x-intercepts are (-3, 0) and (0, 0) for the first piece.

Set the <u>second piece</u> to zero and solve for x:

\begin{aligned}\implies g(x) & =0\\-\log_4(x-2)+2 & =0\\\log_4(x-2) & =2\end{aligned}

\textsf{Apply log law}: \quad \log_ab=c \iff a^c=b

\begin{aligned}\implies 4^2&=x-2\\x & = 16+2\\x & = 18 \end{aligned}

Therefore, the x-intercept for the second piece is (18, 0).

So the x-intercepts for the piecewise function are (-3, 0), (0, 0) and (18, 0).

<h3><u>Part C</u></h3>

From the graph from part A, and the calculated x-intercepts from part B, the function g(x) is positive between the intervals -3 < x < 0 and 3 ≤ x < 18.

Interval notation:  (-3, 0) ∪ [3, 18)

Learn more about piecewise functions here:

brainly.com/question/11562909

3 0
2 years ago
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