This is the concept of trajectories;
We are required to calculate the time taken for the base ball whose distant to reach the maximum height has been modeled by h=-16t^2+64t+4.2 took to hit the ground. Here we proceed as follows;
At the time when the base ball hits the ground the height,h=0
Thus;
-16t^2+64t+4.2=0
this is a quadratic equation, to solve the quadratic equation we use the formula;
t=[-b+/- sqrt(b^2-4ac)]/(2a)
where;
a=-16,b=64, c=4.2
thus substituting the values in our formula we get:
t=[-64+/-sqrt(64^2-4*(-16)*4.2)]/(-16*2)
t=[-64+/- sqrt(4364.8)]/(-32)
t=[-64+/-66.1]/(-32)
t=4.1 or-0.1
thus the we take the positive value t=4.1 and we conclude that the time taken for the ball to hit the ground was 4.1 seconds
Answer:
0.75
Step-by-step explanation:
if you divide 100 by 4 you get 25 so 25 is 1/4 so 25 times 3 gets 0.75 out of 100
Answer:
The value of y is 1
Step-by-step explanation:
4 - (y - 3) = 3(y + 1) - 4(1 - y)
4 - y + 3 = 3y + 3 - 4 + 4y
7 - y = 7y - 1
7 + 1 = 7y + y
8y = 8
y = 1
Thus, The value of y is 1
<u>-</u><u>TheUnknownScientist</u><u> 72</u>
Answer:
4 feet
Step-by-step explanation:
Sam’s tent, to the nearest tenth
Answer:
number 3
Step-by-step explanation:
