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11111nata11111 [884]
3 years ago
9

Find the equation of a line which passes through (2 4) with a slope of ½​

Mathematics
1 answer:
Norma-Jean [14]3 years ago
4 0

Answer:

The equation of the straight line is  x - 2y +6 =0

Step-by-step explanation:

<u>Explanation:</u>-

Given a point ( 2, 4) and slope m =  \frac{1}{2}

The equation of the straight line passing through the point and having slope 'm'

          y - y₁ = m ( x - x₁)

           y - 4 = \frac{1}{2} ( x - 2)

          2( y -4) = ( x-2)

          2 y - 8 = x -2

          x - 2 y - 2 + 8 =0

          x - 2y + 6 =0

The equation of the straight line is  x - 2y +6 =0

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Write an equation that represents the line. Use exact numbers
mestny [16]

The equation that represents the line is:

y = \frac{5}{6}x+\frac{8}{3}

Step-by-step explanation:

We have to observe the graph to find the points on line

So the points on line are:

(x1,y1) = (4,6)

(x2,y2) = (-2,1)

First of all we have to find the slope

m = \frac{y_2-y_1}{x_2-x_1}\\= \frac{1-6}{-2-4}\\=\frac{-5}{-6}\\=\frac{5}{6}

Equation of line is given by:

y=mx+b

Putting the value of slope

y = \frac{5}{6}x +b

Putting (4,6) in the equation

6 = \frac{5}{6}(4)+b\\6 = \frac{20}{6} +b\\b = 6 - \frac[20}{6}\\b = \frac{36-20}{6}\\b = \frac{16}{6}\\b = \frac{8}{3}

Putting the value of b

y = \frac{5}{6}x+\frac{8}{3}

Hence,

The equation that represents the line is:

y = \frac{5}{6}x+\frac{8}{3}

Keywords: Equation of line, slope

Learn more about equation of line at:

  • brainly.com/question/537230
  • brainly.com/question/5345266

#LearnwithBrainly

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3 years ago
A= 1/2 h(a+b) solve for b
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Answer and Step-by-step explanation:

Solve for b.

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Divide by h and multiply by 2 from both sides.

\frac{2A}{h} = a+ b

Subtract a from both sides.

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Help. Find the slop and reduce
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Slope = (-1 + 3)/(-4 + 3) = 2/-1 = -2

answer
slope of PQ = -2
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Warren was drawing a shape on the grid below. He started at (3,0) and drew a line to (3,5), then to (5,3), then to (7,5) and fin
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Answer:

M

Step-by-step explanation:

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Explanation:

Use the identities ...

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