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11111nata11111 [884]
3 years ago
9

Find the equation of a line which passes through (2 4) with a slope of ½​

Mathematics
1 answer:
Norma-Jean [14]3 years ago
4 0

Answer:

The equation of the straight line is  x - 2y +6 =0

Step-by-step explanation:

<u>Explanation:</u>-

Given a point ( 2, 4) and slope m =  \frac{1}{2}

The equation of the straight line passing through the point and having slope 'm'

          y - y₁ = m ( x - x₁)

           y - 4 = \frac{1}{2} ( x - 2)

          2( y -4) = ( x-2)

          2 y - 8 = x -2

          x - 2 y - 2 + 8 =0

          x - 2y + 6 =0

The equation of the straight line is  x - 2y +6 =0

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Let's plug in what we know.

The slope is 3/4.

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To find b, we want to plug in a value that we know is on this line: in this case, I will use the point (4, -2). Plug in the x and y values into the x and y of the standard equation.

-2 = 3/4(4) + b

To find b, multiply the slope and the input of x(4)

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Now, subtract 3 from both sides to isolate b.

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Plug this into your standard equation.

y = 3/4x - 5

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Hope this helps!

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