Answer:
Let the integers are p and q.
In case both integers are positive or negative, you add the numbers up and apply their sign to the sum.
<u>Examples:</u>
- 10 + 88 = 98
- -20 + (-15) = -35
In case one of the integers is negative and one positive.
Use absolute value in this case.
Subtract the numbers and apply the sign of the number with the greater absolute value.
<u>Examples:</u>
- - 10 + 15 = |15 - 10| = |5| = 5
- - 15 + 10 = - |15 - 10| = - |5| = -5
Answer:
Step-by-step explanation:
<h3>Given expression</h3>
<h3>Simplify the expression in steps as below</h3>
Used properties in solution process:
Answer: D. No automatic fees charged to the account.
If I had the chance to teach a foreigner regarding checking and savings account at the banks in the United States, I would remind him/her of this important note. There are no automatic fees charged to the account therefore, consumers cannot protect their rights.
Answer:
5a. -0.4 m/s²
5b. 290 m
6. 12.9 s
7. 100 s
8. 17.2 km/hr
Step-by-step explanation:
5. "While approaching a police officer parked in the median, you accelerate uniformly from 31 m/s to 27 m/s in a time of 10 s.
a. What is your acceleration?
b. How far do you travel in that time?"
Given:
v₀ = 31 m/s
v = 27 m/s
t = 10 s
Find: a and Δx
v = at + v₀
(27 m/s) = a (10 s) + (31 m/s)
a = -0.4 m/s²
Δx = ½ (v + v₀) t
Δx = ½ (27 m/s + 31 m/s) (10 s)
Δx = 290 m
6. "If a pronghorn antelope accelerates from rest in a straight line with a constant acceleration of 1.7 m/s², how long does it take for the antelope to reach a speed of 22 m/s?"
Given:
v₀ = 0 m/s
v = 22 m/s
a = 1.7 m/s²
Find: t
v = at + v₀
(22 m/s) = (1.7 m/s²) t + (0 m/s)
t = 12.9 s
7. "A 1200 kg airplane starts from rest and moves forward with a constant acceleration of 5 m/s² along a runway that is 250 m long. How long does it take the plane to travel the 250 m?"
Given:
v₀ = 0 m/s
a = 5 m/s²
Δx = 250 m
Find: t
Δx = v₀ t + ½ at²
(250 m) = (0 m/s) t + ½ (5 m/s²) t²
t = 100 s
8. "During a marathon, a runner runs the first 10 km in 0.58 hours, the next 10 km in 0.54 hours and the last 10 km in 0.62 hours. What is the average speed of the runner during that marathon?"
This isn't a constant acceleration problem, so there's no need for a chart.
Average speed = total distance / total time
v = (10 km + 10 km + 10 km) / (0.58 hr + 0.54 hr + 0.62 hr)
v = 30 km / 1.74 hr
v = 17.2 km/hr
Answer:
-19,6830x^26
Step-by-step explanation:
The nth term of a geometric sequence is expressed as;
Tn -= ar^n-1
a is the first term
is the number of terms
r is the common ratio
Given
a = -10x^8
r = 30x^10/-10x^8 = -3x^2
n = 10
Substitute
a10 = (-10x^8)(-3x^2)^10-1
a10 = (-10x^8)(-3x^2)^9
a10 = -10x^8)(19,683)x^18
a10 = -19,6830x^26
Hence the tenth term is -19,6830x^26
