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3 years ago

Choose the methods of solving quadratic equations

2 answers:

6 0

It depends on the specific quadratic equation, but factoring, completing the square and quadratic formula (perhaps simplifying)

If you need help with solving one I can help you :D

sp2606 [1]3 years ago

6 0

There are 4

factoring
completing the square
quadratic formula
square root method (used when there's no b term)

You might be interested in

Wha is 5÷312 in long division

bezimeni [28]

The answer is 62 with a remainder of 2.

Hope this helps!

5 0

3 years ago

Find the value of 3a-4b if a=-2 and b=1

iVinArrow [24]

Hey there!
Let's plug in our values:
3(-2) - 4(1) =
-6-4 =
-10.
Hope this helps!

8 0

3 years ago

For the function f(x) = x + 5 , what is the order pair for the point on the graph when X=4w

pantera1 [17]

F(x) = x + 5; x = 4w

f(4w) = 4w + 5

Answer: B - (4w; 4w + 5)

5 0

3 years ago

1) Find the value of x.

Alex_Xolod [135]

x=6

Explanation:

The opposite side is 35, and the sides are still the same length, but on the side it has +5, so when you multiply 5 by 6 you'll get 30. 6×5=30

30+5=35.

Therefore,

x is going to have to be 6.

8 0

2 years ago

PLEASE HEP ME QUICK!!!!: Tom travels between the two mile markers shown and then finds his average speed in miles per hour. Sele

slega [8]

Answer:

$speed=\frac{195\ miles}{3\ hours}$

$3\ hours=\frac{195\ miles}{speed}$

$3\ hours*(speed)=195\ miles$

Step-by-step explanation:

we know that

The speed is equal to divide the distance by the time

Let

x -----> the distance in miles

y ----> the time in hours

$speed=\frac{x}{y}$

we have

The distance is equal to subtract 35 miles from 230 miles

$x=230-35=195\ miles$

The time is equal to subtract 1:30 pm from 4:30 pm

$y=4:30\ pm-1:30\ pm=3\ hours$

substitute in the formula of speed

$speed=\frac{195\ miles}{3\ hours}$

Isolate 3 hours

$3\ hours=\frac{195\ miles}{speed}$

Isolate 195 miles

$195\ miles=3\ hours*(speed)$

7 0

3 years ago