Answer:
Its Break-even Point. The Inn Has 75 Rooms That Are Rented At $60 A Night. Operating Costs Are As Follows. Salaries Utilities Depreciation Maintenance Maid Service Other Costs $10,600 Per Month 2,400 Per Month 1,500 Per Month 800 Per Month 8 Per Room 34 Per Room Determine The Inn's Break-even Point In ..
Step-by-step explanation:
Answer:
The solutions are π/4, 3π/4,5π/4,7π/4
Step-by-step explanation:
The given equation is
6sin²(x) = 3
Divide by 6 to get:
This implies that;
If
in the first quadrant
in the second quadrant.
If
in the third quadrant
If we are going to analyze the problem very well, the equation that we will be able to make would be: 2x + 6y = 72
72 is the oz of water conditioner to use in his fish tanks.
small tanks would require 2 oz of conditioner
large tanks would require 6 oz of conditioner
There is only one point which satisfy's the above equation.That is the points of (0, 12) and (36, 0)
Answer:
Step-by-step explanation:
The principal was compounded monthly. This means that it was compounded 12 times in a year. So
n = 12
The rate at which the principal was compounded is 4%. So
r = 4/100 = 0.04
The formula for compound interest is
A = P(1+r/n)^nt
A = total amount in the account at the end of t years. The total amount is given as $100000.
1) When t is 1,
100000 = P(1+0.04/12)^12×1
100000 = P(1+0.0033)^12
100000 = P(1.0033)^12
P = 100000/1.04
P = $96154
2) When t is 10
100000 = P(1+0.04/12)^12×10
100000 = P(1+0.0033)^120
100000 = P(1.0033)^120
P = 100000/1.485
P = $67340
3) When t is 20
100000 = P(1+0.04/12)^12×20
100000 = P(1+0.0033)^240
100000 = P(1.0033)^240
P = 100000/2.2
P = $45455
4) When t is 30
100000 = P(1+0.04/12)^12 × 30
100000 = P(1+0.0033)^360
100000 = P(1.0033)^360
P = 100000/3.274
P = $30544
5) When t is 40
100000 = P(1+0.04/12)^12 × 40
100000 = P(1+0.0033)^480
100000 = P(1.0033)^480
P = 100000/4.862
P = $20568
6)When t is 50
100000 = P(1+0.04/12)^12 × 50
100000 = P(1+0.0033)^600
100000 = P(1.0033)^600
P = 100000/7.22
P = $13850
