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3 years ago

What is the correct way to write 1/4% as a decimal

Mathematics

2 answers:

Yakvenalex [24]3 years ago

7 0

Answer:

Step-by-step explanation:

well 1/4% wouldnt be 25% because they are 25% = 0.25 = 1/4

the percentage sign changes everything

since it is 1/4% rather than 1/4 by itself

1/4% = 0.25%

if you want to know the percent as a decimal you move the "." to the left twice

(or divide by 100)

so that means that the decimal of 0.25% would be 0.0025

WINSTONCH [101]3 years ago

5 0

Answer:

1/0.04 = 25

Step-by-step explanation:

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Could someone help me answer this? <br> Solve -2log8(x + 1) = -8.<br> Thanks so much!

drek231 [11]

Step one, divide both sides by -2
log8(x+1)=4

if the base is 10, and the 8 is together with (x+1): (cannot tell from the way it is written)
8(x+1)=10^4=10000
x+1=1250
x=1249

if the 8 is a base,
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3 years ago

A triangle has an area of 36 square centimeters and a base of 6 centimeters. Find the height. a. 6 cm c. 18 cm b. 12 cm d. 10 cm

melamori03 [73]

Answer:

Step-by-step explanation:

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3 years ago

Jacob mixes ⅓ cup of yellow paint for every ⅕ cup of blue paint to make green paint. How many cups of yellow paint are needed fo

Nana76 [90]

Answer:

$\frac{5}{3}$ cups

Step-by-step explanation:

Jacob mixes $\frac{1}{3}$ cup of yellow paint for every $\frac{1}{5}$ cup of blue paint to make green paint.

The ratio of yellow paint to blue paint = $\frac{1}{3} : \frac{1}{5}$

= 5:3

$\frac{1}{5}$ cup of blue paint = $\frac{1}{3}$ cup of yellow paint

1 cup of blue paint = $\frac{1}{3}$ ÷ $\frac{1}{5}$ cup of yellow paint

⇒ $\frac{1}{3}$ ÷ $\frac{1}{5}$

⇒ $\frac{5}{3}$

Hence, For 1 cup of blue paint needed $\frac{5}{3}$ cups of yellow paint.

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3 years ago

Determine the equation of the line that passes through the points of intersection of the graphs of the quadratic functions f(x)

timofeeve [1]

Answer: $x-2y-2=0$

Step-by-step explanation:

Given :

$f(x) = x^2 - 4 \\ g(x) = - 3x^2 + 2x + 8$

Point of intersection :

$f(x)=g(x)\\x^2-4=-3x^2+2x+8\\4x^2-2x-12=0\\2x^2-x-6=0\\2x^2-4x+3x-6=0\\2x(x-2)+3(x-2)=0\\(x-2)(2x+3)=0\\x=2\,,\,\frac{-3}{2}$

$x=2\,;f(2)=2^2-4=0\\x=\frac{-3}{2}\,; f\left ( \frac{3}{2} \right )=\left ( \frac{3}{2} \right )^2-4=\frac{-7}{4}=-1.75$

So, we have points $\left ( 2,0 \right )\,,\,\left ( -1.5,-1.75\ \right )$

Equation of line passing through two points $\left ( x_1,y_1 \right )\,,\,\left ( x_2,y_2 \right )$ is given by $y-y_1=\frac{y_2-y_1}{x_2-x_1}\left ( x-x_1 \right )$