Question

Write a function rule for the volume of the cylinder shown at the right with a height 3 in more than 4 times the radius of the cylinder's base. What is the volume of the cylinder when it has a radius of 2 in?

Answer 1

we know that

The volume of a cylinder is equal to

$V=\pi r^{2} h$

where

r is the radius  of the base

h is the height of the cylinder

In this problem

$h=3+4r$

For $r=2\ in$

Find the value of h

$h=3+4*2$

$h=11\ in$

Find the volume of the cylinder

$V=\pi*2^{2}*11$

$V=44*\pi\ in^{3}= 138.2\ in^{3}$

therefore

the answer is

The volume of a cylinder is equal to $138.2\ in^{3}$

Answer 2

Volume of a cylinder = π r² h

radius = 2 inches
height = 3 inches more than 4 times the radius. 4(2) + 3 = 8 + 3 = 11 inches

Volume of a cylinder = 3.14 * (2in)² * 11 inches
Volume of a cylinder = 3.14 * 4in² * 11 inches
Volume of a cylinder = 138.16 in³