Answer:
A linear equation in the standard form is written as:
y = a*x +b
where a is the slope and b is the y-intercept.
If we know that the line passes through the points (a, b) and (c, d), then the slope can be written as:
a = (d - b)/(c - a)
So we know that our line passes through the points (8, -1) and (2, -5)
then the slope will be:
a = (-5 - (-1) )/(2 - 8) = (-4/-6) = 2/3
Then our line is something like:
y = (2/3)*x + b
to find the value of b, we can use the fact that we know that our line passes through the point (2, -5)
this means that when x = 2, we must have y = -5
replacing these values in the equation we get:
-5 = (2/3)*2 + b
-5 = 4/3 + b
-5 - 4/3 = b
-15/3 - 4/3 = b
-19/3 = b
then the equation is:
y = (2/3)*x - 19/3
(in the question you wrote the point-slope form, but you can see that it does not work for the second point, so there may be a mistake there, as the slope is missing)
The actual equation in the point-slope form is:
y + 1 = (2/3)*(x - 8)
