8x2y2 – + 4x4

A=14+(n-1)(8) solve please step by step

Rashid [163]

Answer:

$a = 8n + 6$

Step-by-step explanation:

Step 1: Distribute

$a = 14 + (n - 1)(8)$

$a = 14 + (8 * n) + (8 * -1)$

$a = 14 + 8n - 8$

$a = 8n + 6$

Answer: $a = 8n + 6$

5 0

3 years ago

Read 2 more answers

3x+112=5x+100 what is the answer I don't get it

slega [8]

Reorder the terms
112 + 3x = 100 + 5x
112 + 3x + (-5x) = 100 + 5x + (-5x)

Combine the like terms
5x + (-5x) = 0
112 + (-2x) = 100 + 0
112 + (-2x) = 100

112 + (-112) + (-2x) = 100 + (-112)
Combine like terms again
112 + (-112) =0
0 + (-2x) = 100 + (-112)
100 + (-112) = (-112) = (-12)
-2x = -12
-12 / -2 = 6
x = 6 ✓

Check your work
3 * 6 + 112 = 130
5 * 6 + 110 = 130
130 = 130 ✓

3 0

3 years ago

2. It costs Edgar $2.65 one way to ride the bus to work. He uses the bus to go to and from work four days per week. He buys a bo

Maurinko [17]

$27

2.65 x 2 (since he has to go both to and from work each day) = $5.30
Add the daily cost of the water bottle (1.45) to make his total cost for one day, which is 6.75
Multiply this number by 4 (because he goes 4 days a week) to get $27 for one week.

6 0

2 years ago

A consumer group has determined that the distribution of life spans for gas ranges (stoves) has a mean of 15.0 years and a stand

Art [367]

Answer:

b. Mean = 1.6 years, standard deviation - 0.92 years, shape: approximately Normal.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction of normal Variables:

When we subtract normal variables, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

A consumer group has determined that the distribution of life spans for gas ranges (stoves) has a mean of 15.0 years and a standard deviation of 4.2 years. Sample of 35:

This means that:

$\mu_G = 15$