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3 years ago

Question 3.3. Find the LCD of these fractions.

Mathematics

1 answer:

Yakvenalex [24]3 years ago

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Find the value of the variable.

MatroZZZ [7]

Answer:

sin 30=14/x

x=14*2

x=28

and

x=√{28²-14²}

x=14√3

7 0

3 years ago

Enzo is studying the black bear population at a large national park.

Naddik [55]

Answer:

2,973

Step-by-step explanation:

The black bear population B(t), in the park is modeled by the following function:

$B(t) = 2500 \cdot 2^{0.01t}$

Where t is the time(in years) elapsed since the beginning of the study.

We want to determine the black bear population in 25 years time, t=25.

$B(25) = 2500 \cdot 2^{0.01*25}\\=2973.02\\\approx 2973$

There will be 2,973 black bears in 25 years time.

4 0

2 years ago

A tourist first walked 17km with a speed of v km/h. Then he hiked 12 km uphill with the speed that was 2 km/hour less than his o

ExtremeBDS [4]

Answer: $t=\frac{17}{v}+\frac{12}{v-2}$

Step-by-step explanation:

Given: A tourist first walked 17km with a speed of v km/h.

Since $Speed=\frac{distance}{time}$

therefore, $Time=\frac{distance}{speed}$

Let $t_1$ be the time he walked with speed v.

then $t_1=\frac{17}{v}$

Also he hiked 12 km uphill with the speed that was 2 km/hour less than his original speed.

Let $t_2$ be the time he hiked 12 km,

Then $t_2=\frac{12}{v-2}$

The total time for the whole trip is given by:-

$t=t_1+t_2=$

Substitute the values of $t_1$ and $t_2$ in the equation, we get

$t=\frac{17}{v}+\frac{12}{v-2}$

4 0

3 years ago

henry painted a picture of his house on a canvas. the actual width of the driveway is 20 feet. If it is reresented with a width

AnnyKZ [126]

Answer:

5 feet = 1 inch

Step-by-step explanation:

20 / 4 = 5

5 feet = 1 inch

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cint%5Climits%5E3_t%7B%7Cx%2B2%7C%7D%20%5C%2C%20dx%20" id="TexFormula1" title=" \int\limi

photoshop1234 [79]

$\displaystyle\int_{-3}^3|x+2|\,\mathrm dx$

Recall the definition of absolute value:

$|x|=\begin{cases}x&\text{for }x\ge0\\-x&\text{for }x$

So we can split up the integration interval at $x=-2$ and apply this definition to rewrite the integral as

$\displaystyle\int_{-3}^{-2}(-(x+2))\,\mathrm dx+\int_{-2}^3(x+2)\,\mathrm dx$
$=\displaystyle-\int_{-3}^{-2}(x+2)\,\mathrm dx+\int_{-2}^3(x+2)\,\mathrm dx$
$=-\left(\dfrac12x^2+2x\right)\bigg|_{x=-3}^{x=-2}+\left(\dfrac12x^2+2x\right)\bigg|_{x=-2}^{x=3}$
$=\dfrac12+\dfrac{25}2=13$

7 0

3 years ago